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aniked [119]
3 years ago
14

I need this ASAP PLZ...helpp ...i will give brainlies to the correct answer

Mathematics
2 answers:
adoni [48]3 years ago
5 0
Solve by factoring
x = -12
x = 3
Vinil7 [7]3 years ago
5 0
X= -12
x= 3

solve for x by factoring ! hope this helps
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What is the value of the function at x = 2?
frozen [14]
The value is 2 because it just is.
4 0
3 years ago
Read 2 more answers
What is the circumference of a circle that has a radius of 10 inches​
Naddika [18.5K]

Answer:

\huge\colorbox{orange}{circumference =  > 2 π\: r}

<h2>=>2*10*π</h2><h2>=>20π</h2>

or

<h2>=>20*3.14</h2><h2>=>62.8 inches</h2>
8 0
3 years ago
Write the equation of a parabola that has a vertex of (-2,5.5) and passes through the point (-2.5,2.5).
vekshin1

The equation of a parabola that has a vertex of (-2, 5.5) and passes through the point (-2.5, 2.5) is  y=-12(x+2)^2+5.5

The vertex form of the equation of a parabola is:

y=a(x-h)^2+k

where (h, k) is the vertex of the parabola

(x, y) is the point that the parabola passes through

The vertex, (h, k) = (-2, 5.5)

The point, (x, y) = (-2.5, 2.5)

Substitute h = -2, k = 5.5, x = -2.5, and y = 2.5 into the equation to solve for a.

2.5=a(-2.5-(-2))^2+5.5\\\\2.5=a(-2.5+2)^2+5.5\\\\2.5-5.5=a(-2.5+2)^2\\\\-3=a(-0.5)^2\\\\-3=0.25a\\\\a = \frac{-3}{0.25} \\\\a = -12

Therefore, the equation of the parabola is:

y=-12(x-(-2))^2+5.5\\\\y=-12(x+2)^2+5.5

Learn more here: brainly.com/question/25667732

5 0
3 years ago
Help solve : a=1 and c=SQRT 2
melomori [17]
A^2 + b^2 = c^2

1^2 + b^2 = (sqrt(2))^2

1 + b^2 = 2

b^2 = 1

b = 1
8 0
3 years ago
2/3÷ 1/2 = 2/3 x 2/1 =​
trasher [3.6K]
I think that it is false
8 0
3 years ago
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