All categories

3 years ago

2 and 3/8 minus 1/4 times 1/8

Mathematics

1 answer:

sveta [45]3 years ago

3 0

Answer:

2 11/32 or 75/32

Step-by-step explanation:

2 3/8 - 1/4 x 1/8= 2 3/8 - 1/32= 19/8- 1/32= 76/32 - 1/32= 75/32= 2 11/32

You might be interested in

A curve is given by y=(x-a)√(x-b) for x≥b, where a and b are constants, cuts the x axis at A where x=b+1. Show that the gradient

ankoles [38]

<u>Answer:</u>

A curve is given by y=(x-a)√(x-b) for x≥b. The gradient of the curve at A is 1.

<u>Solution:</u>

We need to show that the gradient of the curve at A is 1

Here given that ,

$y=(x-a) \sqrt{(x-b)}$ --- equation 1

Also, according to question at point A (b+1,0)

So curve at point A will, put the value of x and y

$0=(b+1-a) \sqrt{(b+1-b)}$

0=b+1-c --- equation 2

According to multiple rule of Differentiation,

$y^{\prime}=u^{\prime} y+y^{\prime} u$

so, we get

${u}^{\prime}=1$

$v^{\prime}=\frac{1}{2} \sqrt{(x-b)}$

$y^{\prime}=1 \times \sqrt{(x-b)}+(x-a) \times \frac{1}{2} \sqrt{(x-b)}$

By putting value of point A and putting value of eq 2 we get

$y^{\prime}=\sqrt{(b+1-b)}+(b+1-a) \times \frac{1}{2} \sqrt{(b+1-b)}$

$y^{\prime}=\frac{d y}{d x}=1$

Hence proved that the gradient of the curve at A is 1.

7 0

2 years ago

5(2n - 4) = 9(n + 2)

Wewaii [24]

1. Distribute
5(2n-4)
10n-20

9(n+2)
9n+18

10n-20=9n+18

2. Combine like terms
combine the terms with “n”, and then combine the other numbers.

Hope this helps!

8 0

2 years ago

If p is a point with polar coordinates (r,thetaθ), the rectangular coordinates (x,y) of p are given by xequals=_______ and y

Anuta_ua [19.1K]

Answer:

x = r cos theta and y = r sin theta

Step-by-step explanation:

cos theta = x / r so:-

x = r cos theta

and sin theta = y / r, so

y = r sin theta

5 0

2 years ago

Pls help i dont understand :( will give Brainliest + 25 Points

umka21 [38]

It’s D. 4 is the one next to X because that’s what is changing and -3 is the y intercept which comes after X

3 0

3 years ago

Read 2 more answers

FIRST CORRECT ANSWER GETS BRAINLIEST AND 50 POINTS.

AnnyKZ [126]

Answer:

A) $5^3*5^{-4}=5^{3-4}=5^{-1}=\frac{1}{5}$ (Yes. It has a value between zero and one.)

B) $\frac{3^5}{3^{-6}}=3^{5-\left(-6\right)}=3^{5+6}=3^{11}=177147$ (No. It does not have a value between zero and one.)

C) $\left(\frac{1}{4}\right)^3* \left(\frac{1}{4}\right)^2=\left(\frac{1}{4}\right)^{3+2}=\left(\frac{1}{4}\right)^5=\frac{1^5}{4^5}=\frac{1}{1024}$ . (Yes. It has a value between zero and one.)

D) $\frac{\left(-7\right)^5}{\left(-7\right)^7}=\left(-7\right)^{5-7}=\left(-7\right)^{-2}=\frac{1}{\left(-7\right)^2}=\frac{1}{49}$ (Yes. It has a value between zero and one.)

4 0

3 years ago

Read 2 more answers