5.
y=mx+b
y=1/2x+3
6.
y=mx+b
y=-2x+5
(Just plug in the numbers)
6 - 4x = (3 - x)
Subtract 6 from both sides, as well as adding x to both sides.
-4x + x = 3 - 6
Add like terms.
-3x = -3
Divide both sides by -3.
x = 1
So, your answer is c) All real, numbers because all of the other answer choices are wrong.
We know this because a) and b) are incorrect. To know if they are incorrect, you just plug in the numbers. When 2 and -2 are plugged into the equation, it is incorrect. So, you solve the equation, and you now know that it is not D) because there is a solution.
So, once again, your answer is C.
~Hope I helped!~
Answer:
5/2 or c
Step-by-step explanation:is correct trust me
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1. Find the equation of the line AB. For reference, the answer is y=(-2/3)x+2.
2. Derive a formula for the area of the shaded rectange. It is A=xy (where x is the length and y is the height).
3. Replace "y" in A=xy with the formula for y: y= (-2/3)x+2:
A=x[(-2/3)x+2] This is a formula for Area A in terms of x only.
4. Since we want to maximize the shaded area, we take the derivative with respect to x of A=x[(-2/3)x+2] , or, equivalently, A=(-2/3)x^2 + 2x.
This results in (dA/dx) = (-4/3)x + 2.
5. Set this result = to 0 and solve for the critical value:
(dA/dx) = (-4/3)x + 2=0, or (4/3)x=2 This results in x=(3/4)(2)=3/2
6. Verify that this critical value x=3/2 does indeed maximize the area function.
7. Determine the area of the shaded rectangle for x=3/2, using the previously-derived formula A=(-2/3)x^2 + 2x.
The result is the max. area of the shaded rectangle.