Answer:
Larger number is 13 and Smaller number is 4.
Step-by-step explanation:
Let the larger number be x.
Also let the smaller number be y.
We need to find the two numbers.
Given:
The larger of two numbers is twice the smaller increased by five.
framing in equation form we get;
⇒equation 1
Also Given:
Three times the larger exceeds double the smaller by 31
⇒equation 2
Now Substituting the value of x from equation 1 in equation 2 we get;

Now Using Distributive property we get;

Combining the like terms we get;

Now Using Subtraction property we get;

Now Using Division property we get;

Now Substituting value of y in equation 1 we will find the value of x.

Hence Larger number is 13 and Smaller number is 4.