1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Dmitry_Shevchenko [17]
3 years ago
11

On the set of axes below, graph the function y=|x+1|.

Mathematics
2 answers:
Nata [24]3 years ago
8 0
Post the image it would help a lot.

viva [34]3 years ago
3 0
If you know what a y=|x| graph looks like (a v with the point at the origin) then y=|x+1| is the same graph shifted to the left one unit. 

Otherwise, I would plug in x-values to find corresponding y-values so you can plot points. For example, when x is 0, y=1

Hope this helps
You might be interested in
What is equivalent to 5d + 4e + 3d + 2e
il63 [147K]
8d plus 6e is the answer
8 0
3 years ago
Read 2 more answers
Find the common difference for the given sequence 1.05, 1.1, 1.15, 1.2,... A)0.005 B)0.05 C)0.5
torisob [31]
It's actually going to be B)0.05,if you add 1.05 to 0.05 then you'll get 1.1 Hope this helps:)
6 0
2 years ago
A walkway is being installed around a rectangular playground. The playground is 30 feet by 12 feet, and the total area of the pl
worty [1.4K]

Answer:

10.3

Step-by-step explanation:

From these question, we can illustrate the playground has a small rectangle with 30x12ft

the walkway is around it with an area of 1288ft²

the playground area = 30 x 12 = 360ft²

the length dimension of the walkway is 30+y+y( these is because the walkway is round the playground in two sides) = 30 +2y

the breadth dimension of the walkway is 12+y+y ( these is because the walkway is round the playground in two sides) = 12+2y

Area of walkway = (30+2y)(12+2y)= 30(12+2y)+2y(12+2y) = 360+60y+24y+4y²= 360+84y+4y²

The total area = 1288ft²

The total area = area of walkway - area of playground

1288ft² = 360+84y+4y² - 360

choose like terms

1288 = 360-360+84y+4y²

1288 = 84y+4y²

divide by 4

322= 21y+y²

y²+21y-322 =0

using quadratic formula

x= (-b±√b²-4ac)/2a = {-21±√21²-4(1)(-322)}/2x1 =  {-21±√441+1288}/2x1  = -21±√1729/2

-21+√1729/2   -21-√1729/2

√1729 = 41.5812457726

-21+√1729/2   -21-√1729/2

{-21+41.5812457726}/2   {-21-41.5812457726}/2

20.5812457726/2          -62.5812457726/2

10.2906228863              -31.2906228863

we disregard the negative sign

our width is 10.2906228863 ≅10.3

4 0
2 years ago
Read 2 more answers
Which of the following statements are true? (Select all that apply)
avanturin [10]

Answer:

a and c I'm 99percent shure

5 0
3 years ago
A box contains red, purple and green beads in the ratio 4:6:7 There are 1428 more green beads than red beads.
Rama09 [41]

Answer:

3332 green beads

Step-by-step explanation:

8 0
3 years ago
Other questions:
  • What is the equation of the line with m=6 that goes through the point (1,4)
    10·1 answer
  • Find the equations of the two tangents to the curve y= 2x2 + 18 which pass through the origin.
    5·1 answer
  • Drag the tiles to the boxes to form the correct pairs. not all tiles will be used.
    8·2 answers
  • How is each function related to y=x? Graph the function by translating the parent function
    9·1 answer
  • Evaluate 6 + \sqrt(14) + 2 - \sqrt(9) x 2<br><br> Answers are in the picture:
    9·1 answer
  • $7450 is invested at 8.0% compounded continuously. How long will it take for the balance to reach $14900? Round your answer to t
    5·1 answer
  • In △JKL, _______ is the leg opposite ∠J and _______ is the leg adjacent to ∠J. segment LK; segment JK segment LK; segment JL seg
    11·1 answer
  • An orange weighs 1/5 of a pound cut the orange into 8 slices. How much does each slice weigh?
    5·1 answer
  • Find the 11th term of the progression 4, 8, 16, ...​
    13·1 answer
  • Molly is painting a model house and needs to know how much paint she will need. She knows the surface area of the prism is 216 s
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!