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Elza [17]
3 years ago
5

if the welcome gold nugget were turned into 3 equal sized gold brick how many troy ounces would each brick weight​

Mathematics
1 answer:
MAXImum [283]3 years ago
4 0

Answer: Each brick woukd weigh 772 troy ounces

Step-by-step explanation:

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PLZ HELP, GIVING BRAINLIEST!! Which of these choices are equivalent to the expression i^85? a. i^7 b. i^26 c. i^41 d. i^99
SCORPION-xisa [38]

Answer:

I think the answer is a.i^7

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3 years ago
Answer this correctly I’ll give brainalist + 10 points
Ganezh [65]

the sum of supplementary angles is 180 degree

therefore

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5 0
2 years ago
A cable hangs between two poles of equal height and 35 feet apart. At a point on the ground directly under the cable and x feet
gayaneshka [121]

Answer:

293.38 pounds

Step-by-step explanation:

We are given that

Distance between poles=35 feet

h(x)=10+0.1(x^{1.5})

Weight of cable=10.4 per linear foot

We have to find the weight of the cable.

Differentiate w.r.t

h'(x)=0.1(1.5)x^{0.5}=0.15x^{0.5}

s=2\int_{0}^{17.5}\sqrt{1+(h'(x))^2}dx

s=2\int_{0}^{17.5}\sqrt{1+(0.15x^{0.5})^2}dx

s=2\int_{0}^{17.5}\sqrt{1+0.0225x}dx

Let 1+0.0225x=t

dx=\frac{1}{0.0225}dt

s=\frac{2}{0.0225}\int_{0}^{17.5}\sqrt{t}dt

s=\frac{2}{0.0225}\times\frac{2}{3}[t^{\frac{3}{2}}]^{17.5}_{0}

s=2\times \frac{2}{3\times0.0225}[(1+0.0255x)^{\frac{3}{2}]^{17.5}_{0}

s=\frac{4}{3\times 0.0225}((1+0.0225(17.5))^{\frac{3}{2}-1)

s=28.21

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8 0
3 years ago
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ollegr [7]

Answer:

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Step-by-step explanation:

Common denominator: 18

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Reduce:

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6 0
3 years ago
Read 2 more answers
What is a reasonable estimate for the problem ?
umka21 [38]

Answer:

A is the correct answer

5 0
2 years ago
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