(2-6i)+(4+3i) standard form

Mathematics

1 answer:

Mazyrski [523]3 years ago

5 0

6-3i. You add common factors. 2+4 is 6 and -6i and 3i is negative 3i

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Solve the system using substitution. Show your work. x = -4y + 9 x - y = 4

FromTheMoon [43]

Answer:

please what should we found? is it the value of ×or y

6 0

3 years ago

Read 2 more answers

Help!!!!!!!!!!!!!!!!!!!!

lapo4ka [179]

Well... the segment FG = 4x + 3, the segment GH = 7x - 12, now, the

segment FH = FG + GH, those two fellows added up, and we know that FG and GH are both equal halves because G is the midpoint.

thus, FG = GH
or

$\bf 4x+3=7x-12\implies 3+12=7x-4x\implies 15=3x
\\\\\\
\cfrac{15}{3}=x\implies \boxed{5=x}\\\\
-------------------------------\\\\
thus\qquad 
\begin{cases}
\overline{FG}=4x+3\\
4(5)+3\\
23\\
------\\
\overline{GH}=7x-12\\
7(5)-12\\
23
\end{cases}\impliedby equal\ halves
\\\\\\
\overline{FH}=23+23\implies \overline{FH}=46\implies 6y-2=46
\\\\\\
6y=46+2\implies y=\cfrac{48}{6}$

and fairly sure, you know how much that is.

7 0

2 years ago

10 Pts Multiplying fractions: 5 1 — x — = 6 2

Flauer [41]

Multiply the numerators together. Multiply the denominators together. Then reduce if necessary.

$\dfrac{first~numerator}{first~denominator} \times \dfrac{second~numerator}{second~denominator} = \dfrac{(first~numerator)\times(second~numerator)}{(first~denominator)\times(second~denominator)}$