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hodyreva [135]
3 years ago
15

Which of the following is not a requirement of the binomial probability​ distribution? Choose the correct answer below. A. Each

trial must have all outcomes classified into two categories. B. The procedure has a fixed number of trials. C. The probability of a success remains the same in all trials. D. The trials must be dependent.
Mathematics
1 answer:
Fudgin [204]3 years ago
7 0
A i hope it helps each trial must have all outcomes classified into two categories
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A medical researcher wondered if there is a significant difference between the mean birth weight of boy and girl babies. Random
Yuliya22 [10]

Answer:

b) independent samples t-test

t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154  

p_v =2*P(t_{8}>0.154) =0.881  

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).  

Step-by-step explanation:

The system of hypothesis on this case are:  

Null hypothesis: \mu_1 = \mu_2  

Alternative hypothesis: \mu_1 \neq \mu_2  

Or equivalently:  

Null hypothesis: \mu_1 - \mu_2 = 0  

Alternative hypothesis: \mu_1 -\mu_2\neq 0  

Our notation on this case :  

n_1 =5 represent the sample size for group 1  

n_2 =5 represent the sample size for group 2  

We can calculate the mean and deviation for eaach group with the following formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s = \sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X_1 =5.92 represent the sample mean for the group 1  

\bar X_2 =5.74 represent the sample mean for the group 2  

s_1=1.88 represent the sample standard deviation for group 1  

s_2=1.81 represent the sample standard deviation for group 2  

If we see the alternative hypothesis we see that we are conducting a bilateral test and with independnet samples t test.

b) independent samples t-test

The statistic is given by this formula:  

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{\sqrt{\frac{s^2_1}{n_1}}+\frac{S^2_2}{n_2}}  

And now we can calculate the statistic:  

t=\frac{(5.92 -5.74)-(0)}{\sqrt{\frac{1.88^2}{5}}+\frac{1.81^2}{5}}=0.154  

The degrees of freedom are given by:  

df=5+5-2=8

And now we can calculate the p value using the altenative hypothesis:  

p_v =2*P(t_{8}>0.154) =0.881  

So with the p value obtained and using the significance level given \alpha=0.05 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the mean of the group 1 (boys) is NOT significantly different than the mean for the group 2 (Girls).  

7 0
3 years ago
A bag contains tiles. 3 tiles of red, 6 tiles of green, 3 tiles are blue. A tile will be randomly selected from the bag. What is
ruslelena [56]

Answer:

The probability is 0.5 tiles will be green

Step-by-step explanation:

Hope this helps

7 0
3 years ago
Which linear inequality is represented by the graph?
yarga [219]

Answer:

y is less than -2x+3

Step-by-step explanation:

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Find the value of x
romanna [79]

they are 2 similar triangles, one is smaller than the other. they are in the ratio of 2:1,

hence 7x =56÷2

7x=28

x=4

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3 years ago
PLEASE HELP. Write the equation in slope-intercept form for the line that contains the points
madam [21]

Answer:

y=2x-11

Step-by-step explanation:

3 0
3 years ago
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