Please help? I don’t understand this

Mathematics

1 answer:

Brut [27]1 year ago

3 0

Answer:

Please see the graph below

Step-by-step explanation:

The table is just selecting numbers for x and then solving for what y would be. Once we have the ordered pairs (x,y) We can graph the points and see the line.

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Find the solution to the system of 5x+2y=-24 x-y=5

Mashutka [201]

So to do this, we have to get rid of one of the variables by adding or subtracting the two equations together.
I will get rid of y. So, we can multiply the second equation by 2. This gives us
2x-2y=10
Now, we can add both equations
This gives us 7x=-14
Therefore, x = -2
Plug that into another equation.
-10 + 2y=-24
Therefore, y = -7

Hope this helped!! :D

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4 years ago

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Alja [10]

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3 years ago

A student was given the line y=2/3x-1 and the point (-7, 1/2) and asked to find an equation that went through the given point an

Colt1911 [192]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of y=2/3x-1 anyway?

$\bf \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}~\hspace{7em}y=\stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x-1 \\\\[-0.35em] ~\dotfill$

$\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}$

so, notice, "one of his mistakes" is that he used 3/2 as the slope, not -3/2.

so, we're really looking for a line whose slope is -3/2 and runs through (-7, 1/2).

$\bf (\stackrel{x_1}{-7}~,~\stackrel{y_1}{\frac{1}{2}})~\hspace{10em} slope = m\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\cfrac{1}{2}=-\cfrac{3}{2}[x-(-7)]\implies y-\cfrac{1}{2}=-\cfrac{3}{2}(x+7) \\\\\\ y-\cfrac{1}{2}=-\cfrac{3}{2}x-\cfrac{21}{2}\implies y=-\cfrac{3}{2}x-\cfrac{21}{2}+\cfrac{1}{2}\implies y=-\cfrac{3}{2}x-10$