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3 years ago

BRAINLIEST

Mathematics

2 answers:

guapka [62]3 years ago

7 0

Answer:

8(3x - 2)

Explanation:

Factor 24x − 16

24x − 16

= 8(3x − 2)

anygoal [31]3 years ago

3 0

Answer:

Step-by-step explanation:

24x = 8*3*x

16 = 8* 2

Greatest common factor = 8

24x - 16 = 8(3x - 2)

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What should be done to solve the equation? x+14=21 Add 14 to both sides of the equation. Subtract 14 from the left side of the e

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Answer:

Subtract 14 from both sides of the equation.

Step-by-step explanation:

The subtraction property of equality tells you the equal sign only remains valid if you subtract the same value from both sides of the equation.

Here, we want the 14 on the left side to be replaced by 0. Thus we must add its opposite. Since we must do the same thing to both sides of the equation, we must subtract 14 from both sides of the equation.

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The volume of a trapezoidal prism is 24 cubic units. It's height is 6 units, as labeled. What is the area of a trapezoidal base

scZoUnD [109]

Answer:

Area of trapezoidal base = 4 square units.

Step-by-step explanation:

We know that volume of a prism is known as :

$V = B \times h$

where B is Area of Base

and h is Height of prism

NOTE: Formula for Volume of a prism can be generalized as above irrespective of the type of base it has (base can be of type triangle, rectangle, square or trapezoidal etc).

Here, we are given that Base is trapezoidal.

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And we have to find out the value of B.

Putting the above values in above formula:

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Hence, area of trapezoidal base = 4 square units.

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3 years ago

Find the complex fourth roots of 81(cos(3π/8)+isin(3π/8)). a) Find the fourth root of 81. b) Divide the angle in the problem by

WARRIOR [948]

Answer:

The answer is below

Step-by-step explanation:

Let a complex z = r(cos θ + isinθ), the nth root of the complex number is given as:

$z_1=r^{\frac{1}{n} }(cos(\frac{\theta +2k\pi}{n} )+isin(\frac{\theta +2k\pi}{n} )),\\k=0,1,2,.\ .\ .,n-1$

Given the complex number z = 81(cos(3π/8)+isin(3π/8)), the fourth root (i.e n = 4) is given as follows:

$z_{k=0}=81^{\frac{1}{4} }(cos(\frac{\frac{3\pi}{8} +2(0)\pi}{4} )+isin(\frac{\frac{3\pi}{8} +2(0)\pi}{4} ))=3[cos(\frac{3\pi}{32} )+isin(\frac{3\pi}{32})] \\z_{k=0}=3[cos(\frac{3\pi}{32} )+isin(\frac{3\pi}{32})]\\\\z_{k=1}=81^{\frac{1}{4} }(cos(\frac{\frac{3\pi}{8} +2(1)\pi}{4} )+isin(\frac{\frac{3\pi}{8} +2(1)\pi}{4} ))=3[cos(\frac{19\pi}{32} )+isin(\frac{19\pi}{32})] \\z_{k=1}=3[cos(\frac{19\pi}{32} )+isin(\frac{19\pi}{32})]\\\\$

$z_{k=2}=81^{\frac{1}{4} }(cos(\frac{\frac{3\pi}{8} +2(2)\pi}{4} )+isin(\frac{\frac{3\pi}{8} +2(2)\pi}{4} ))=3[cos(\frac{35\pi}{32} )+isin(\frac{35\pi}{32})] \\z_{k=2}=3[cos(\frac{35\pi}{32} )+isin(\frac{35\pi}{32})]\\\\z_{k=3}=81^{\frac{1}{4} }(cos(\frac{\frac{3\pi}{8} +2(3)\pi}{4} )+isin(\frac{\frac{3\pi}{8} +2(3)\pi}{4} ))=3[cos(\frac{51\pi}{32} )+isin(\frac{51\pi}{32})] \\z_{k=3}=3[cos(\frac{51\pi}{32} )+isin(\frac{51\pi}{32})]$

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3 years ago

I need help with this as fast as possible, I have no idea what it could be-

sergejj [24]

Can’t see the pic .........................

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2 years ago