Answer:
84
Step-by-step explanation:
<em>i dont know if this is right or not but basscially you do 60 divided by 5/7 and yea....</em>
Answer:
The x-coordinate of another point is zero
Step-by-step explanation:
step 1
Find the slope between the two given points
The formula to calculate the slope between two points is equal to
we have
substitute in the formula
Simplify
step 2
Find the x-coordinate of another point
we have
(x,-3)
we know that
If the other point is on the line, then the slope between the other point and any of the other two points must be the same
so
Find the slope between the points
Remember that
substitute in the formula
the denominators must be the same


therefore
The x-coordinate of another point is zero
16 m³
Step-by-step explanation:
Step 1:
Here we are going to find the volume of square pyramid.
Volume of square pyramid =
×
× 
Here base = 4 m
Height = 3 m
Step 2:
Volume = (1/3) × (4 × 4) × 3
= 16 m³
Answer:
- Solution of equation ( q ) = <u>1</u><u>6</u>
Step-by-step explanation:
In this question we have given an equation that is <u>3 </u><u>(</u><u> </u><u>q </u><u>-</u><u> </u><u>7</u><u> </u><u>)</u><u> </u><u>=</u><u> </u><u>2</u><u>7</u><u> </u>and we have asked to solve this equation that means to find the value of <u> </u><u>q</u><u> </u><u>.</u>
<u>Solution : -</u>

<u>Step </u><u>1</u><u> </u><u>:</u> Solving parenthesis :

<u>Step </u><u>2</u><u> </u><u>:</u> Adding 21 on both sides :

On further calculations we get :

<u>Step </u><u>3 </u><u>:</u> Dividing by 3 from both sides :

On further calculations we get :

- <u>Therefore</u><u>,</u><u> </u><u>solution</u><u> </u><u>of </u><u>equation</u><u> </u><u>(</u><u> </u><u>q </u><u>)</u><u> </u><u>is </u><u>1</u><u>6</u><u> </u><u>.</u>
<u>Verifying</u><u> </u><u>:</u><u> </u><u>-</u>
Now we are very our answer by substituting value of q in the given equation . So ,
<u>Therefore</u><u>,</u><u> </u><u>our </u><u>solution</u><u> </u><u>is </u><u>correct</u><u> </u><u>.</u>
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<u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>