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laila [671]
3 years ago
13

Evaluate the limit. lim x-> infinity n/3^x

Mathematics
1 answer:
Sav [38]3 years ago
7 0

Answer:

0

Step-by-step explanation:

Find the following limit:

lim_(x->∞) 3^(-x) n

Applying the quotient rule, write lim_(x->∞) n 3^(-x) as (lim_(x->∞) n)/(lim_(x->∞) 3^x):

n/(lim_(x->∞) 3^x)

Using the fact that 3^x is a continuous function of x, write lim_(x->∞) 3^x as 3^(lim_(x->∞) x):

n/3^(lim_(x->∞) x)

lim_(x->∞) x = ∞:

n/3^∞

n/3^∞ = 0:

Answer:  0

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Answer:

y=6x+8

Step-by-step explanation:

Write in slope-intercept form, y=mx+b.

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a rectangular flying carpet in 1 and 1/2 meters wide and 2 meters long what is the area of the carpet
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Answer:

D) 20

Step-by-step explanation:

x^2 + (y - 2)^2=100

This can be rewritten as

(x-0)^2 + (y - 2)^2=10^2

This is in the form

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3 years ago
If f(x)=x*−81 and g(x)=(x−9)−1(x+9), find g(x)×f(x).
Nostrana [21]
F(x) = x²-81

g(x) = (x-9) -1(x+9)

= (x-9) -x-9


g(x) • f(x)



= [x²-81 ] • [ (x-9) -x-9 ]

=[ x²-81 ] • [ (x-x -9-9) ]
= [ x²-81 ] •[0-18]
= [ x²-81] •[ -18]

= -18•x² +-81•-18
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7 0
3 years ago
What is the area of a cross section that is parallel to face ABCD ?
Hunter-Best [27]
To solve this problem you must apply the proccedure shown below:
 1. The problem asks for the area of a cross section that is parallel <span>to face ABCD. As is parallel to that face, you have can calculate its area as following:
 A=12 cm x 6 cm
 2. Therefore, the result is:
 A=72 cm</span>²
 The answer is: T<span>he area of a cross section that is parallel to face ABCD is 72 cm</span>².
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