Answer:
Step-by-step explanation:
I can't really tell from the image but it looks like the lines are parallel to each other
Theo's overall change is $21 because since they are different signs of adding integers, you subtract the absolute value of the greatest to the least and the higher absolute value u use the same sign as
Answer: ![m\angle EYL=96\°](https://tex.z-dn.net/?f=m%5Cangle%20EYL%3D96%5C%C2%B0)
Step-by-step explanation:
For this exercise you need to use the formula for calculate the measure of the angle formed by two tangents intersecting outside of a circle. This is:
![Angle\ formed \ by\ two\ tangents = \frac{1}{2}(Difference\ of\ Intercepted\ Arcs)](https://tex.z-dn.net/?f=Angle%5C%20formed%20%5C%20by%5C%20two%5C%20tangents%20%3D%20%5Cfrac%7B1%7D%7B2%7D%28Difference%5C%20of%5C%20Intercepted%5C%20Arcs%29)
According to the information given in the exercise, you know that:
![Angle\ formed \ by\ two\ tangents = m\angle EYL\\\\Difference\ of\ Intercepted\ Arcs=m LVE-mLHE](https://tex.z-dn.net/?f=Angle%5C%20formed%20%5C%20by%5C%20two%5C%20tangents%20%3D%20%20m%5Cangle%20EYL%5C%5C%5C%5CDifference%5C%20of%5C%20Intercepted%5C%20Arcs%3Dm%20LVE-mLHE)
Since there are 360 degrees in a circle, you can determine that:
![mLVE=360\°-mLHE\\\\mLVE=360\°-84\°\\\\mLVE=276\°](https://tex.z-dn.net/?f=mLVE%3D360%5C%C2%B0-mLHE%5C%5C%5C%5CmLVE%3D360%5C%C2%B0-84%5C%C2%B0%5C%5C%5C%5CmLVE%3D276%5C%C2%B0)
Therefore, knowing these values, you can substitute them into the formula given above and the evaluate, in order to find the measure of the angle EYL. This is:
![m\angle EYL=\frac{1}{2}(276\°-84\°) \\\\m\angle EYL=96\°](https://tex.z-dn.net/?f=m%5Cangle%20EYL%3D%5Cfrac%7B1%7D%7B2%7D%28276%5C%C2%B0-84%5C%C2%B0%29%20%5C%5C%5C%5Cm%5Cangle%20EYL%3D96%5C%C2%B0)
Answer:
![a_n=a_{n-1}+5](https://tex.z-dn.net/?f=a_n%3Da_%7Bn-1%7D%2B5)
Step-by-step explanation:
From the table,
The common difference is
![d=8-3=5](https://tex.z-dn.net/?f=d%3D8-3%3D5)
This means that , we can get the subsequent term by adding 5 to the previous term.
The recursive formula is
![a_n=a_{n-1}+5](https://tex.z-dn.net/?f=a_n%3Da_%7Bn-1%7D%2B5)
The correct choice is A
|5|= 5.
Absolute Value is always positive.