The line y = -3 is a horizontal line. The perpendicular line will be vertical, so will have an equation of the form
x = c
for some constant c.
You want the vertical line to go through the point (4, -6), so the required value of c is the x-value of that point: 4
Your equation is
x = 4
Answer:
or
Step-by-step explanation:
yz-plane has the equation 
where 
is a real constant. The normal vector of this plane (vector perpendicular to the plane) is
If the line is perpendicular to this plane, then it is parallel to the normal vector, so the equation of this line is
where 
are coordinates of the point the line is passing through.
In your case, the line is passing through the point (0,0,8), so the canonical equation of the line is
Write a vector parametrization for this line
Answer:
(0,0) (-2,1) (-4,2) (-6,3) (-8,4)
Step-by-step explanation:
Hope this helps!
Answer:
12 _3/4
Step-by-step explanation:
3/4 + 1/2 + 2 = 3_1/4
16 cups in a gallon
16-3_1/4
=12_3/4
