I have been given the short leg in this 30-60-90 triangle. How do I find the long leg?
1 answer:
Answer:
Please check the answer below.
Step-by-step explanation:
You have been given the short leg in this 30-60-90 triangle.
You must remember that
- The shortest leg is across from the m∠30°,
- Hypotenuse is twice the length of the the shortest leg,
- In order to find the long leg, all you need is to multiply the short leg by
(commonly known as the square root of 3).
For example, if you have the hypotenuse with length units.
In order to get the short side, just divide by 2. i.e. 14/2 = 7 units
In order to find the long leg, all you need is to multiply the short leg by .
i.e. 7 × .
You might be interested in
Take derivitive
note
the derivitive of sec(x)=sec(x)tan(x)
so
remember the quotient rule
the derivitive of
so
the derivitive of
so now evaluate when t=pi
we get
sec(pi)=-1
tan(pi)=0
we get
slope=1/pi
use slope point form
for
slope=m and point is (x1,y1)
equation is
y-y1=m(x-x1)
slope is 1/pi
point is (pi,1/pi)
y-1/π=1/π(x-π)
times both sides by π
πy-1=x-π
πy=x-π+1
y=(1/π)x-1+(1/π)
or, alternately
-(1/π)x+y=(1/π)-1
x-πy=π-1
note
the derivitive of sec(x)=sec(x)tan(x)
so
remember the quotient rule
the derivitive of
so
the derivitive of
so now evaluate when t=pi
we get
sec(pi)=-1
tan(pi)=0
we get
slope=1/pi
use slope point form
for
slope=m and point is (x1,y1)
equation is
y-y1=m(x-x1)
slope is 1/pi
point is (pi,1/pi)
y-1/π=1/π(x-π)
times both sides by π
πy-1=x-π
πy=x-π+1
y=(1/π)x-1+(1/π)
or, alternately
-(1/π)x+y=(1/π)-1
x-πy=π-1