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3 years ago

I have been given the short leg in this 30-60-90 triangle. How do I find the long leg?

Mathematics

1 answer:

Alexxx [7]3 years ago

7 0

Answer:

Please check the answer below.

Step-by-step explanation:

You have been given the short leg in this 30-60-90 triangle.

You must remember that

The shortest leg is across from the m∠30°,

Hypotenuse is twice the length of the the shortest leg,

In order to find the long leg, all you need is to multiply the short leg by $\sqrt{3}$ (commonly known as the square root of 3).

For example, if you have the hypotenuse with length $14$ units.

In order to get the short side, just divide by 2. i.e. 14/2 = 7 units

In order to find the long leg, all you need is to multiply the short leg by $\sqrt{3}$ .

i.e. 7 × $\sqrt{3}$ .

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For a recent year, the rate of first-class postage is as follows:

Law Incorporation [45]

Answer:

$0.95

Step-by-step explanation:

Given that weight of the function = x

Given that cost of the postage for mail having weight less than or equal to 1 oz = $0.44

then to find the equation can be written as

C(x)=0.44 where 0<x<=1

Similarly we can write equation for other parts

C(x)=0.61 where 1<x<=2

C(x)=0.78 where 2<x<=3

C(x)=0.95 where 3<x<=3.5

Now we can write them together as piecewise function as shown in below:

$C(x)=\left\{\begin{matrix}0.44 & 0$

to graph that we just draw horizontal lines for each as none equation contains x on the right side .

3.48 oz is less that 3.5 so we will use $0.95.

7 0

3 years ago

Read 2 more answers

Solve for ppp. 16-3p=\dfrac23p+516−3p= 3 2 p+516, minus, 3, p, equals, start fraction, 2, divided by, 3, end fraction, p, plus

Ksivusya [100]

Given:

The given equation is:

$16-3p=\dfrac{2}{3}p+5$

To find:

The value of p.

Solution:

We have,

$16-3p=\dfrac{2}{3}p+5$

Multiply both sides by 3.

$3(16-3p)=3\left(\dfrac{2}{3}p+5\right)$

$48-9p=2p+15$

Isolating the variable terms, we get

$48-15=2p+9p$

$33=11p$

Divide both sides by 11, we get

$\dfrac{33}{11}=p$

$3=p$

Therefore, the required solution is $p=3$ .

7 0

3 years ago

based only on the inormation given in the diagram, which congruence theorems or postulates could be the given as reasons why abc

Fudgin [204]

Answer: 1. HA cannot be a reason to show given triangles are congruent as it is not given that they have an acute angle common in both the triangles.

2. HL can be a reason to show given triangles are congruent as the triangles are right triangle with equal legs and hypotenuse.

3. SAS can be a reason to show given triangles are congruent as there are two congruent sides in both triangles and included angles ∠A=∠D=90° [right angle].

4. LA cannot be a reason to show given triangles are congruent as it is not given that they have an acute angle common in both the triangles.

5. AAS cannot be a reason to show given triangles are congruent as it is not given that they have two angles common in both the triangles.

6.SSS can be a reason to show given triangles are congruent as it is shown that all the sides of one triangle is congruent to the other.

HOPE THIS HELPS

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3 years ago

Need a graphing calculator for math class he finds a $60 model on sale for 15% off if he decides to buy the calculator how much

miss Akunina [59]

$60-15%=$51 so $51 is the answer

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3 years ago

For the equation y=7x-2, what is the rate of change? What does it mean? It is a linear function where the rate of change is the

podryga [215]

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3 years ago