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Colt1911 [192]
3 years ago
15

Line segment EF has a length of 5 units. It is translated 5 units to the right on a coordinate plane to obtain line segment E′F′

. What is the length of E′F′?
5 units
6 units
10 units
25 units
Mathematics
2 answers:
mylen [45]3 years ago
7 0

Answer:

25 units

Step-by-step explanation:

just multiply by 5

Dimas [21]3 years ago
3 0

Answer 25 units

Step-by-step explanation:

cause there are already 5 so multipy 5

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Hi!

5^2 is 25

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Find: (4x2y3 + 2xy2 – 2y) – (–7x2y3 + 6xy2 – 2y)
lidiya [134]
The answer is 11, -4, 0

5 0
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Solve: 3y+5=-1 . What’s the solution?
Harman [31]

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Step-by-step explanation:

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If ef bisects angle ceb,angle cef=7x+31 and angle feb=10x-3
Nastasia [14]

Given : Angle  < CEB is bisected by EF.

< CEF = 7x +31.

< FEB = 10x-3.

We need to find the values of x and measure of < FEB, < CEF  and < CEB.

Solution: Angle  < CEB is bisected into two angles < FEB and < CEF.

Therefore,   < FEB = < CEF.

Substituting the values of < FEB and < CEF, we get

10x -3 = 7x +31

Adding 3 on both sides, we get

10x -3+3 = 7x +31+3.

10x = 7x + 34

Subtracting 7x from both sides, we get

10x-7x = 7x-7x +34.

3x = 34.

Dividing both sides by 3, we get

x= 11.33.

Plugging value of x=11.33 in < CEF = 7x +31.

We get

< CEF = 7(11.33) +31 =  79.33+31 = 110.33.

< FEB  = < CEF =  110.33 approximately

< CEB = < FEB +  < CEF  = 110.33 +110.33 = 220.66 approximately



7 0
2 years ago
Solve using the quadratic formula: 2n^2= 6n - 2
bekas [8.4K]

Answer:

n_1=(3 + 1\sqrt{5} )/2\\\\n_2=(3 - 1\sqrt{5} )/2

Step-by-step explanation:

2n^2= 6n - 2\\\\2n^2-6n+2=0\\\\a=2\\\\b=-6\\\\c=2

n=(-b \pm \sqrt{b^2-4ac} )/2a\\\\n=(-(-6) \pm \sqrt{(-6)^2-4(2)(2)} )/2(2)\\\\n=(6 \pm \sqrt{36-16} )/4\\\\n=(6 \pm \sqrt{20} )/4\\\\n=(6 \pm 2\sqrt{5} )/4\\\\n=(3 \pm 1\sqrt{5} )/2\\\\n_1=(3 + 1\sqrt{5} )/2\\\\n_2=(3 - 1\sqrt{5} )/2

3 0
2 years ago
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