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2 years ago

Mrs. Flynn baked 6 more cookies than Mrs. Jones did. If together they baked 42 cookies, how many did Mrs. Jones bake?

Mathematics

1 answer:

galben [10]2 years ago

8 0

Answer:

Mrs. Jones baked 18 cookies

Mrs. Flynn baked 24 cookies

Step-by-step explanation:

42-6=36(to find 2x the number mrs jones baked)

36/2=18(how cookies baked by mrs jones)

18+6=24(how many mrs flynn baked)

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Question 1: find the volume of a cube whose total surface area is 486cm^2

lapo4ka [179]

<h3>The volume of cube is 729 cubic centimeter</h3>

Solution:

The surface area of cube is given as:

$Surface\ area = 6a^2$

Where, "a" is the length of side of cube

Given that, surface area = 486 square centimeter

$486 = 6a^2\\\\a^2 = \frac{486}{6}\\\\a^2 = 81\\\\a = 9$

Find the volume of cube:

$volume\ of\ cube = a^3\\\\volume\ of\ cube = 9^3\\\\volume\ of\ cube = 9 \times 9 \times 9\\\\volume\ of\ cube = 729$

Thus volume of cube is 729 cubic centimeter

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3 years ago

If a kitten weighs 4 pounds what is the approximate mass of the kitten in kilograms

Tatiana [17]

It is around 1.81 kilograms

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3 years ago

Ashley draws a square that has a diagonal of

xz_007 [3.2K]

The diagonal is the hypotenuse of a right triangle with the sides of the square as legs.
By Pythagoras (s = side)
s^2 + s^2 = 15^2
2s^2 = 225
s^2 = 112.5
s = sqrt(112.5)
s = 10.6 cm (to the nearest tenth)

5 0

3 years ago

Read 2 more answers

The probability that Ismael makes a basket is 7/10. If he shoots 100 baskets, how many can he expect to make?

sdas [7]

Answer:

70 baskets

Step-by-step explanation:

Let b be the number of baskets he will make if he shoots 100 baskets.

$\frac{7}{10} =\frac{b}{100} \\700=10b (now divide by 10 from both sides)\\$

7 0

3 years ago

Suiting at 6 a.m., cars, buses, and motorcycles arrive at a highway loll booth according to independent Poisson processes. Cars

dem82 [27]

Answer:

Step-by-step explanation:

From the information given:

the rate of the cars = $\dfrac{1}{5} \ car / min = 0.2 \ car /min$

the rate of the buses = $\dfrac{1}{10} \ bus / min = 0.1 \ bus /min$

the rate of motorcycle = $\dfrac{1}{30} \ motorcycle / min = 0.0333 \ motorcycle /min$

The probability of any event at a given time t can be expressed as:

$P(event \ (x) \ in \ time \ (t)\ min) = \dfrac{e^{-rate \times t}\times (rate \times t)^x}{x!}$

∴

(a)

$P(2 \ car \ in \ 20 \ min) = \dfrac{e^{-0.20\times 20}\times (0.2 \times 20)^2}{2!}$

$P(2 \ car \ in \ 20 \ min) =0.1465$

$P ( 1 \ motorcycle \ in \ 20 \ min) = \dfrac{e^{-0.0333\times 20}\times (0.0333 \times 20)^1}{1!}$

$P ( 1 \ motorcycle \ in \ 20 \ min) = 0.3422$

$P ( 0 \ buses \ in \ 20 \ min) = \dfrac{e^{-0.1\times 20}\times (0.1 \times 20)^0}{0!}$

$P ( 0 \ buses \ in \ 20 \ min) = 0.1353$

Thus;

P(exactly 2 cars, 1 motorcycle in 20 minutes) = 0.1465 × 0.3422 × 0.1353

P(exactly 2 cars, 1 motorcycle in 20 minutes) = 0.0068

(b)

the rate of the total vehicles = 0.2 + 0.1 + 0.0333 = 0.3333

the rate of vehicles with exact change = rate of total vehicles × P(exact change)

$= 0.3333 \times \dfrac{1}{4}$

= 0.0833

∴

$P(zero \ exact \ change \ in \ 10 minutes) = \dfrac{e^{-0.0833\times 10}\times (0.0833 \times 10)^0}{0!}$

P(zero exact change in 10 minutes) = 0.4347

The probability of the 7th motorcycle after the arrival of the third motorcycle is:

$P( 4 \ motorcyles \ in \ 45 \ minutes) =\dfrac{e^{-0.0333\times 45}\times (0.0333 \times 45)^4}{4!}$

$P( 4 \ motorcyles \ in \ 45 \ minutes) =0.0469$

Thus; the probability of the 7th motorcycle after the arrival of the third one is = 0.0469

P(at least one other vehicle arrives between 3rd and 4th car arrival)

= 1 - P(no other vehicle arrives between 3rd and 4th car arrival)

The 3rd car arrives at 15 minutes

The 4th car arrives at 20 minutes

The interval between the two = 5 minutes

For Bus:

P(no other vehicle other vehicle arrives within 5 minutes is)

= $\dfrac{6}{12} = 0.5$

For motorcycle:

$= \dfrac{2 }{12} = \dfrac{1 }{6}$

∴

The required probability = $1 - \Bigg ( \dfrac{e^{-0.5 \times 0.5^0}}{0!} \times \dfrac{e^{-1/6}\times (1/6)^0}{0!} \Bigg)$

= 1- 0.5134

= 0.4866

6 0

3 years ago