All categories

3 years ago

Giving brainlist to whoever answers

Mathematics

1 answer:

SashulF [63]3 years ago

7 0

Answer:

I think the answer should be D, (tell me if i'm wrong).

You might be interested in

Name the following segment or point.

Mamont248 [21]

Answer:

Step-by-step explanation:

It's where the altitudes meet

5 0

3 years ago

Please help with this (for a test tomorrow), if you could show all working out for the 2 examples, sin(<img src="https://tex.z-d

ELEN [110]

Answer:

[tex][pi]

Step-by-step explanation:

Hope it is helpful

6 0

3 years ago

QUESTION 11

notsponge [240]

Answer:

Step-by-step explanation:

3( 2 + 2 ) - 4

3( 4 ) - 4

12-4

3 0

3 years ago

A 4ft piece of pipe needs to be divided into pieces that are 2/3ft long. How many pieces are made? How many remaining?

Katen [24]

4ft divided by 2/3ft

4/1 divided by 2/3

4/1 times 3/2 is 12/2 or 6 pieces, 0 remaining.

3 0

3 years ago

a boy is standing on a pole of height 14.7m throws a stone upwards. it moves in a vertical line slightly away from the pole and

fomenos

Answer:

The time taken for the upward motion is 1 second. The same time is taken for the downward motion

It reaches a maximum height of 4.9 meters.

Step-by-step explanation:

The equation of motion is:

$x(t) = -4.9t^{2} + 9.8t$

Since the term which multiplies t squared is negative, the graph is concave down, that is, x increases until the vertex, where it reaches it's maximum height, then it decreases.

Vertex of a quadratic equation:

Quadratic equation in the format $x(t) = at^{2} + bt + c$

The vertex is the point $(t_{v}, x(t_{v}))$ , in which

$t_{v} = -\frac{b}{2a}$

In this question:

$x(t) = -4.9t^{2} + 9.8t$

So $a = -4.9, b = 9.8$

Vertex:

$t_{v} = -\frac{9.8}{2*(-4.9)} = 1$

The time taken for the upward motion is 1 second.

$x(t_{v}) = x(1) = 9.8*1 - 4.9*(1)^{2} = 4.9$

It reaches a maximum height of 4.9 meters.

Downward motion:

From the vertex to the ground.

The ground is t when x = 0. So

$-4.9t^{2} + 9.8t = 0$

$4.9t^{2} - 9.8t = 0$

$4.9t(t - 2) = 0$

$4.9t = 0$

$t = 0$

$t - 2 = 0$

$t = 2$

It reaches the ground when t = 2 seconds.

The downward motion started at the vertex, when t = 1.

So the duration of the downward motion is 2 - 1 = 1 second.

5 0

3 years ago