When the dependent variable increases when the independent variable increases, the rate of change is

- 5 - 2 (a - b) + 2 (a - b) -3 (a - b) + 3 = ?

zzz [600]

Collect like terms and you'll get -2 - 3(a - b)

7 0

3 years ago

Read 2 more answers

Answer the question in the picture pls WORTH 50 POINTS PLUS BRAINLIEST FOR FIRST CORRECT ANSWER

Alexus [3.1K]

Answer:

A

Step-by-step explanation:

Step 1: Simplify both sides of the inequality.

−y+4≥8

Step 2: Subtract 4 from both sides.

−y+4−4≥8−4

−y≥4

Step 3: Divide both sides by -1.

−y

−1

≥

4

−1

y≤−4

5 0

3 years ago

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The jewerly store is having a sale. Necklaces that were regulaey priced at $23.50 are on dale for $18.80. What is the percentage

AveGali [126]

What we need to do is find the difference between the two numbers to find the difference in price and then figure out what the percent of 23.5 that is

23.50-18.80=4.7

now we'll set up a proportion

4.7 x
----- = -----
23.5 100

then cross multiply and divide

100×4.7=470/23.5=20

the percent of decrease is 20%

I hope I've helped!

8 0

3 years ago

Find the distance between the points (-1,-7) and (8,-9). The answer must be a whole number or a fully simplified radical express

ruslelena [56]

Answer:

The answer is

<h2> $\sqrt{85} \: \: \: units$ </h2>

Step-by-step explanation:

The distance between two points can be found by using the formula

$d = \sqrt{ ({x1 - x2})^{2} + ({y1 - y2})^{2} } \\$

where

(x1 , y1) and (x2 , y2) are the points

From the question the points are

(-1,-7) and (8,-9)

The distance between them is

$d = \sqrt{( { - 1 - 8})^{2} + ({ - 7 + 9})^{2} } \\ = \sqrt{ ({ - 9})^{2} + {2}^{2} } \\ = \sqrt{81 + 4}$

We have the final answer as

$\sqrt{85} \: \: \: units$

Hope this helps you

3 0

3 years ago

2. Margie Spencer wants to have $100,000 in her savings account in 20 years. If her account pays 6.6% annual

WITCHER [35]

$~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill & \$100000\\ P=\textit{original amount deposited}\\ r=rate\to 6.6\%\to \frac{6.6}{100}\dotfill &0.066\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{semiannually, thus two} \end{array}\dotfill &2\\ t=years\dotfill &20 \end{cases}$

$100000=P\left(1+\frac{0.066}{2}\right)^{2\cdot 20}\implies 100000=P(1.033)^{40} \\\\\\ \cfrac{100000}{1.033^{40}}=P\implies 27288.97\approx P$

7 0

2 years ago