You can draw a quadrilateral with two sets of parallel lines and no right angles?

1 answer:

8 0

Yes you can. The quadrilateral that you would get is called parallelogram. It has 2 paris of parallel lines. and 2 pairs of equal angles. one pair is angles that are less than 90 degrees and other one is where 2 angles are greater than 90 degrees each. Therefore there isnt any right angle there and you got yourself quadrilateral. of these 2 parallel lines are of equal lenght than you get something called rhombus.

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1. Find the vertex of the following: y = (x - 4)(x - 10) *

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Answer:

1. (7,-9)

2. (4,0) and (10,0)

3. (3,0) and (-3,0)

4. (0,-9)

5. (-1,-32)

Step-by-step explanation:

To find the vertex use the formula

$\frac{-b}{2a}$

First make the equation into a quadratic equation.

$(x-4)(x-10)\\x^{2} -10x-4x+40\\x^{2} -14x+40$

Now it is in the form

$ax^{2} +bx+c=0$

Now we can substitute the values

$\frac{-(-14)}{2(1)} \\\frac{14}{2} \\7$

Now we have 7 as our x value for the vertex we can substitute for y,

$x^{2} -14x+40=y\\(7)^{2} -14(7)+40=y\\49-98+4=y\\y=-9$

So the vertex for 1 is (7,-9)

To find the intercepts for 2 & 3, they basically already give it to you. You just need to find a value for x for x-4 that will equal it to 0 and another for x for x-10 that will equal it to 0.

$x-4=0\\x=4\\\\x-10=0\\x=10$