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2 years ago

Using the given points and line, determine the slope of the line. (-3, 0) and (2, 7)

1 answer:

4 0

Slope for (x₁, y₁) and (x₂, y₂): (-3, 0) and (2, 7)

Slope: (y₂ -y₁) / (x₂ -x₁)

Slope: ( 7 - 0) / (2 - -3) = 7/(2 + 3)

<span>Slope = 7/5
</span>

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I’m so confused on how to do it

Monica [59]

Answer:

785.4

Step-by-step explanation:

The formula to find the surface area of a cylinder is

2* pi* radius* height + 2* pi* 2radius.

2( 3.14) (5) (20)= 628

2 (3.14* 5*5)= 157

628+ 157= 785.

8 0

2 years ago

you currently have 24 credit hours and a 2.8 gpa you need a 3.0 gpa to get into the college. if you are taking a 16 credit hours

Juliette [100K]

Answer:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

Step-by-step explanation:

For this case we know that the currently mean is 2.8 and is given by:

$\bar X = \frac{\sum_{i=1}^n w_i *X_i }{24} = 2.8$

Where $w_i$ represent the number of credits and $X_i$ the grade for each subject. From this case we can find the following sum:

$\sum_{i=1}^n w_i *X_i = 2.8*24 = 67.2$

And for this case we want a gpa of 3.0 taking in count that in this semester he/ she is going to take 16 credits so then the new mean would be given by:

$\bar X_f = \frac{\sum_{i=1}^n w_i *X_i+w_f *X_f }{24+16} = 3.0$

And we can solve for $\sum_{i=1}^n w_f *X_f$ and solving we got:

$3.0 *(24+16) =\sum_{i=1}^n w_i *X_i +\sum_{i=1}^n w_f *X_f$

And from the previous result we got:

$3.0 *(24+16) =67.2 +\sum_{i=1}^n w_f *X_f$

And solving we got:

$\sum_{i=1}^n w_f *X_f =120 -67.2= 52.8$

And then we can find the mean with this formula:

$\bar X_2 = \frac{\sum_{i=1}^n w_f *X_f}{16}= \frac{52.8}{16}=16=3.3$

So then we need a 3.3 on this semester in order to get a cumulate gpa of 3.0

6 0

2 years ago

Write an equation of a line that passes through the point (3,2) and is parallel to the line y=3x-4

disa [49]

Parallel lines should have the same slope. Therefore, you know which point it passes through and the slope. Plug in the points and slop into slope-intercept form to find b. Please refer to the picture.

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2 years ago

Paul plans to buy a movie that has a regular price of $19.99. It is on sale for 25% off, but Paul will have to pay 6% sales tax.

marissa [1.9K]

B is your answer for this question

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2 years ago

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PLEASE HELP ME!!!! WILL MARK BRAINLIEST

FromTheMoon [43]

Answer:

Step-by-step explanation:

Pythagoras's theorem dictates that a squared + b squared = c squared when talking about sides on right angled triangles with a and b being flat sides and c being the hypotenuse which gives us the forumula below

3 squared + 4 squared = 25 route 25 = 5

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2 years ago

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