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melamori03 [73]
4 years ago
10

How many line segments are parallel to FE ?

Mathematics
2 answers:
Leni [432]4 years ago
8 0

Answer 2 line segments are parallel to FE


daser333 [38]4 years ago
7 0

Answer:

Three line segments. AB, CD, and GH

Step-by-step explanation: none of these line segments would ever intersect if you were to extend them to infinity. Follow each line segment with you eyes and extend them if you have to, but the ones that intersect the original line segment cannot be parallel, but those that dont cross and wont cross are parallel.

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An air-filled rubber ball has a diameter of 6 in. If the air pressure within the ball is increased until the diameter becomes 7
Yakvenalex [24]

we are given

An air-filled rubber ball

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d=7in

we can use formula of the average normal strain in the rubber

\delta =\frac{\pi d - \pi d_0}{\pi d_0}

now, we can plug values

and we get

\delta =\frac{\pi*7 - \pi*6}{\pi* 6}

\delta =0.16667in/in...........Answer

4 0
4 years ago
WHOEVER ANSWERS CORRECTLY GETS 10 POINTS PLUS BRAINLIEST. MAKE SURE TO REFER TOO UPPER BOUND AND LOWER BOUND WHEN DOING THE QUES
Vinvika [58]

Answer:

Capacity of 60000 litres "to 1 significant figure" means that lower bound is 54449, upper bound is 64999.

=> 10% of that capacity is more than 54449/10 = 5444.9 litres

Tony pours in 5400 litres of water "to 2 significant figure" means that lower bound is 5349, upper bound is 5444.

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4 0
3 years ago
What does 11 to the 3rd power equal
WITCHER [35]
1331 11times 11 times 11
6 0
4 years ago
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Help me plz find the value of x for which QR is parallel to RS
erik [133]

Given:

QR is parallel to RS.

To find:

The value of x.

Solution:

In the given figure, we have,

PR=12

RT=2x-2&#10;

QS=21

ST=3x-1

Using basic proportionality theorem (BPT), we get

\dfrac{PR}{RT}=\dfrac{QS}{ST}

\dfrac{12}{2x-2}=\dfrac{21}{3x-1}

On cross multiplication, we get

12(3x-1)=21(2x-2)

36x-12=42x-42

36x-42x=12-42

-6x=-30

Divide both sides by -6.

x=\dfrac{-30}{-6}

x=5

Therefore, the value of x is 5.

6 0
3 years ago
The sum of three consecutive odd numbers is 63. Find the numbers.
Westkost [7]

Answer:

19, 21, 23

Step-by-step explanation:

Let the first odd number be n.

Then the second, consecutive odd number will be (n+2).

And the third will be (n+4).

We know that they sum to 63. Hence, we can write the following equation:

n+(n+2)+(n+4)=63

Solve for n. Combine like terms:

3n+6=63

Subtract 6 from both sides:

3n=57

Divide both sides by 3:

n=19

Hence, the first odd number is 19.

Therefore, our sequence is: 19, 21, 23.

Note: If we get an even or non-integer value for our n, then there are no three consecutive odd integers that exists that sum to 63.

5 0
4 years ago
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