we are given
An air-filled rubber ball


we can use formula of the average normal strain in the rubber

now, we can plug values
and we get

...........Answer
Answer:
Capacity of 60000 litres "to 1 significant figure" means that lower bound is 54449, upper bound is 64999.
=> 10% of that capacity is more than 54449/10 = 5444.9 litres
Tony pours in 5400 litres of water "to 2 significant figure" means that lower bound is 5349, upper bound is 5444.
Because 5444<5444.9, then clearly he is not correct when he said " I have filled more than 10% of the container"
Given:
QR is parallel to RS.
To find:
The value of x.
Solution:
In the given figure, we have,


Using basic proportionality theorem (BPT), we get


On cross multiplication, we get




Divide both sides by -6.


Therefore, the value of x is 5.
Answer:
19, 21, 23
Step-by-step explanation:
Let the first odd number be n.
Then the second, consecutive odd number will be (n+2).
And the third will be (n+4).
We know that they sum to 63. Hence, we can write the following equation:

Solve for n. Combine like terms:

Subtract 6 from both sides:

Divide both sides by 3:

Hence, the first odd number is 19.
Therefore, our sequence is: 19, 21, 23.
Note: If we get an even or non-integer value for our n, then there are no three consecutive odd integers that exists that sum to 63.