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3 years ago

I need step by step explanation for this!

Mathematics

2 answers:

damaskus [11]3 years ago

5 0

Answer:

Step-by-step explanation:

13 - 1 = 12
12 ÷ 2 = 6
Put 6 and 1 together: 61

Therefore, the number is 61

Let's check:

6 × 2 = 12
12 + 1 = 13

The sum of the two digits is 13, and we got that, so we are correct. The number is 61.

Mkey [24]3 years ago

5 0

Answer:

Step-by-step explanation:

let unit digit=x

ten's digit=y

then x+y=13

x=13-y

also x=2y+1

13-y=2y+1

13-1=2y+y

3y=12

y=12/3=4

x=13-4=9

so number =10×4+9=49

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T=1/p+1/q make q the subject

Lady bird [3.3K]

Answer:

q = $\frac{p}{tp-1}$

Step-by-step explanation:

Given

t = $\frac{1}{p}$ + $\frac{1}{q}$

Multiply through by pq to clear the fractions

tpq = q + p ( subtract q from both sides )

tpq - q = p ← factor out q from each term on the left side

q(tp - 1) = p ← divide both sides by (tp - 1)

q = $\frac{p}{tp-1}$

8 0

3 years ago

Angle X is the larges angle in the triangle XYZ. Angle Y is the smallest angle. How does the sum of the measures of angles Y and

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Dear Dollster444, the sum of angles Y and Z is bigger than Y.

3 0

3 years ago

Which value of w makes 14 = 11+ 6a true statement? 8 Choose 1 answer: PLEASEEEE HELP

Lorico [155]

Answer:

I think D

Step-by-step explanation:

7 0

3 years ago

Drag a statement or reason to each box to complete the proof.

astra-53 [7]

Answer:

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2. Division Property of Equality

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5 0

4 years ago

What are all of the real roots of the following polynomial? f(x) = x4 - 13x2 + 36

GREYUIT [131]

ANSWER

A. -3, -2, 2, and 3

EXPLANATION

The given polynomial function is,

$f(x) = {x}^{4} - 13 {x}^{2} + 36$

To find the real roots, we equate the function to zero to obtain;

${x}^{4} - 13 {x}^{2} + 36 = 0$

We can solve this equation as a quadratic equation in
${x}^{2}.$

Thus we rewrite the equation as,

$({x}^{2})^{2} - 13 {x}^{2} + 36 = 0$

We split the middle term to get,

$({x}^{2})^{2} - 9 {x}^{2} - 4 {x}^{2} + 36 = 0.$

We factor to get,

${x}^{2} ( {x}^{2} - 9) - 4( {x}^{2} - 9) = 0$

We factor to get,

$( {x}^{2} - 9)( {x}^{2} - 4) = 0$

Either

${x}^{2} - 9 = 0$
or

${x}^{2} - 4 = 0$

$x = \pm \sqrt{9} \: or \: x = \pm \sqrt{4}$
$x = \pm3 \: or \: x = \pm2$

$x=-3,-2,2,3$

The correct answer is A

5 0

4 years ago

Read 2 more answers