Let f(x)=3x^2+2.

The chart shows the low temperature each day in International Falls, Minnesota, during the month of February 2009. What was the

Nesterboy [21]

I think you have to list all of the temperatures in order from least to greatest during the first week (-31, -29, -9, -8, 3, 4, 6) in which case the median would be -8.

I hope this helps you and if you know the answer is wrong please let me know in the comments and I will take another look at the question to see if I can figure out the correct answer.

6 0

3 years ago

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The area of a rectangular fountain is x2 + 9x + 20 square feet. A 3-foot walkway is built around the fountain. Find the dimensio

Leto [7]

Answer:

(x+11) by (x+10)

Step-by-step explanation:

We know that Area = Length x width

Given: Area = x²+9x+20

Lets sort this out first

Area = x²+5x + 4x + 20

Area = x(x+5) + 4(x+5)

Area = (x+5) (x+4)

Therefore, it is concluded that:

Length 'l' = (x+5) feet

Width 'w' = (x+4) feet

if a 3-foot walkway is built around the fountain, we'll add 3 feet on both sides

Therefore,

Outer Length = (x+5+3+3) = (x+11) feet

Outer Width = (x+4+3+3) = (x+10) feet

Answer:

The fountain is (x+5) by (x+4).

dimensions of the outside border of the walkway are (x+11) by (x+10)

8 0

3 years ago

find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B

SashulF [63]

Answer:

$\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190$

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately $\theta \approx 48$

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

$a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10$

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

$|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3$

$|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5$

And finally we can calculate the angle between the vectors like this:

$cos \theta = \frac{ab}{|a| |b|}$

And the angle is given by:

$\theta = cos^{-1} (\frac{ab}{|a| |b|})$

If we replace we got:

$\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190$

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately $\theta \approx 48$

3 0

3 years ago

Standard rate of pay 40 hours. Gets 175% for overtime. One week Erik works regular 40 hours and has 16 hours of overtime. He mak

devlian [24]

Standard rate of pay 40 hours. Gets 175% for overtime. One week Erik works regular 40 hours and has 16 hours of overtime. He makes $680 that week. Which equation would solve for the standard rate of pay?

7 0

3 years ago

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What is the slope and y- intercept of the line passing through (11,-3) and (7,9)

Misha Larkins [42]

Answer:

Slope is -3, y-intercept is 30

Step-by-step explanation:

You take the two points (11,-3) and (7,9), plug them into the formula y2-y1/x2-x2=m. Now, you have 9-(-3)/7-11 which gives you 12/-4, 12/-4 can be simplified into -3 which is your slope. To find y-intercept you must use the formula y=mx+b. Plug -3, your slope, into m, and any of the coordinates on your line into the y and x; I used (7,9). You solve for b from 9=-3*7+b. -3*7 gives you -21, now you have 9=-21+b, to get b by itself, you add 21 to both sides, 30=b. B is your y-intercept.

7 0

3 years ago