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Which point is on the circle centered at the origin with a radius of 5 units?
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Answer:
Step-by-step explanation:
Given expression is,
f(x) = 8x³ - 6x² - 36x + 27
For zeros of the function,
f(x) = 0
8x³ - 6x² - 36x + 27 = 0
2x²(4x - 3) - 9(4x - 3) = 0
(2x² - 9)(4x - 3) = 0
(2x² - 9) = 0
x² =
x =
x =
Or (4x - 3) = 0
x =
Therefore, all zeros of the given functions are .