Answer:
The proof is explained below.
Step-by-step explanation:
Given m∠ADB = m∠CDB and AD ≅ DC
we have to prove that m∠BAC = m∠BCA and BD⊥ AC
In ΔADO and ΔCDO
∠OAD=∠OCD (∵ADC is an isosceles triangle)
AD=DC (∵Given)
∠ADO=∠CDO (∵Given)
By ASA rule, ΔADO≅ΔCDO
In ΔBAD and ΔBCD
AD=DC (∵ABC is an isosceles triangle)
∠ADB=∠CDB (∵Given)
DB=DB (∵common)
By ASA rule, ΔADB≅ΔCDB
Now, ΔADB≅ΔCDB and ΔADO≅ΔCDO
⇒ ΔADB-ΔADO≅ΔCDB-ΔCDO
⇒ ΔABO≅ΔCBO
Hence, by CPCT, m∠BAC = m∠BCA
Now, we have to prove that BD⊥ AC i.e we have to prove m∠BOA=90°
Now, ΔABO≅ΔCBO therefore by CPCT, m∠BOA = m∠BOC
But, m∠BOA + m∠BOC=180° (linear pair)
⇒ m∠BOA + m∠BOA=180°
⇒ 2m∠BOA=180° ⇒ m∠BOA=90°
Hence, BD⊥ AC
The probability that the cat lands on its feet both times it falls out of a tree is 0.85
<h3>How to determine the probability?</h3>
The probability that the cat lands on its feet is given as:
P(Feet) = 0.92
The probability that it lands on its feet twice is calculated using:
P = P(Feet) * P(Feet)
So, we have:
P = 0.92 * 0.92
Evaluate
P = 0.85
Hence, the probability is 0.85
Read more about probability at
brainly.com/question/251701
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Answer:
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Step-by-step explanation:
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Answer:
- 1728 in³ in a cubic ft
- 3.6 cubic feet (rounded to tenths)
- 2 suitcases
Step-by-step explanation:
For part 2, you have rounded to hundredths. The question asks for the answer rounded to tenths.
__
<u>Part 3</u>
(3.6 ft³)×(1 suitcase)/(2.9 ft³) = 3.6/2.9 suitcases ≈ 1.24 suitcases
Suitcases only come in whole numbers. 1 is too few, so 2 suitcases are needed.
Answer:
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Step-by-step explanation:
