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NNADVOKAT [17]
4 years ago
7

(-b3+ 3b2 + 8) - (? - 5b2 - 9) = 5b3 + 8b2 + 17 ? = DONE

Mathematics
2 answers:
zhuklara [117]4 years ago
8 0

Let's solve for x.

−b3+3b2+8−(x−5b2−9)=5b3+8b2+17

Step 1: Add b^3 to both sides.

−b3+8b2−x+17+b3=5b3+8b2+17+b3

8b2−x+17=6b3+8b2+17

Step 2: Add -8b^2 to both sides.

8b2−x+17+−8b2=6b3+8b2+17+−8b2

−x+17=6b3+17

Step 3: Add -17 to both sides.

−x+17+−17=6b3+17+−17

−x=6b3

Step 4: Divide both sides by -1.

−x

−1

=

6b3

−1

x=−6b3

Answer:

x=−6b3

k0ka [10]4 years ago
8 0

Answer with Step-by-step explanation:

Let ?=x

We have to find the value of x in:

(-b^3+3b^2+8)-(x-5b^2-9)=5b^3+8b^2+17

Adding b^3 on both sides, we get

-b^3+3b^2+8-x+5b^2+9+b^3=5b^3+8b^2+17+b^3

3b^2+8-x+5b^2+9=5b^3+8b^2+17+b^3

Combining the like terms on both side, we get

8b^2+17-x=6b^3+8b^2+17

Subtracting both sides by 8b², we get

8b^2-x+17-8b^2=6b^3+8b^2+17-8b^2

-x+17=6b^3+17

subtracting both sides by 17, we get

-x+17-17=6b^3+17-17

-x=6b^3

Dividing both sides by -1, we get

x=-6b^3

Hence, ? = -6b^3

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PLEASE HELP!!! BRAINLIEST TO CORRECT COMPLETE ANSWER!
notka56 [123]

Answer:

y=16x+1

Step-by-step explanation:

You want to find the equation for a line that passes through the two points:

(1,17) and (2,33).

First of all, remember what the equation of a line is:

y = mx+b

Where:

m is the slope, and

b is the y-intercept

First, let's find what m is, the slope of the line...

The slope of a line is a measure of how fast the line "goes up" or "goes down". A large slope means the line goes up or down really fast (a very steep line). Small slopes means the line isn't very steep. A slope of zero means the line has no steepness at all; it is perfectly horizontal.

For lines like these, the slope is always defined as "the change in y over the change in x" or, in equation form:

So what we need now are the two points you gave that the line passes through. Let's call the first point you gave, (1,17), point #1, so the x and y numbers given will be called x1 and y1. Or, x1=1 and y1=17.

Also, let's call the second point you gave, (2,33), point #2, so the x and y numbers here will be called x2 and y2. Or, x2=2 and y2=33.

Now, just plug the numbers into the formula for m above, like this:

m=  

33 - 17/  2 - 1

or...

m=  16/ 1

or...

m=16

So, we have the first piece to finding the equation of this line, and we can fill it into y=mx+b like this:

y=16x+b

Now, what about b, the y-intercept?

To find b, think about what your (x,y) points mean:

(1,17). When x of the line is 1, y of the line must be 17.

(2,33). When x of the line is 2, y of the line must be 33.

Because you said the line passes through each one of these two points, right?

Now, look at our line's equation so far: y=16x+b. b is what we want, the 16 is already set and x and y are just two "free variables" sitting there. We can plug anything we want in for x and y here, but we want the equation for the line that specfically passes through the two points (1,17) and (2,33).

So, why not plug in for x and y from one of our (x,y) points that we know the line passes through? This will allow us to solve for b for the particular line that passes through the two points you gave!.

You can use either (x,y) point you want..the answer will be the same:

(1,17). y=mx+b or 17=16 × 1+b, or solving for b: b=17-(16)(1). b=1.

(2,33). y=mx+b or 33=16 × 2+b, or solving for b: b=33-(16)(2). b=1.

See! In both cases we got the same value for b. And this completes our problem.

The equation of the line that passes through the points

(1,17) and (2,33)  is   y=16x+1

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