Question

(-b3+ 3b2 + 8) - (? - 5b2 - 9) = 5b3 + 8b2 + 17 ? = DONE

Answer 1

Let's solve for x.

−b3+3b2+8−(x−5b2−9)=5b3+8b2+17

Step 1: Add b^3 to both sides.

−b3+8b2−x+17+b3=5b3+8b2+17+b3

8b2−x+17=6b3+8b2+17

Step 2: Add -8b^2 to both sides.

8b2−x+17+−8b2=6b3+8b2+17+−8b2

−x+17=6b3+17

Step 3: Add -17 to both sides.

−x+17+−17=6b3+17+−17

−x=6b3

Step 4: Divide both sides by -1.

−x

−1

=

6b3

−1

x=−6b3

Answer:

x=−6b3

Answer 2

Answer with Step-by-step explanation:

Let ?=x

We have to find the value of x in:

$(-b^3+3b^2+8)-(x-5b^2-9)=5b^3+8b^2+17$

Adding $b^3$ on both sides, we get

$-b^3+3b^2+8-x+5b^2+9+b^3=5b^3+8b^2+17+b^3$

$3b^2+8-x+5b^2+9=5b^3+8b^2+17+b^3$

Combining the like terms on both side, we get

$8b^2+17-x=6b^3+8b^2+17$

Subtracting both sides by 8b², we get

$8b^2-x+17-8b^2=6b^3+8b^2+17-8b^2$

$-x+17=6b^3+17$

subtracting both sides by 17, we get

$-x+17-17=6b^3+17-17$

$-x=6b^3$

Dividing both sides by -1, we get

$x=-6b^3$

Hence, ? = $-6b^3$