Answer:
Step-by-step explanation:
<u>The quadratic equation in factored form:</u>
- a(x - α)(x - β), where a- leading coefficient, α and β - roots
<u>We have:</u>
<u>Substitute them to get:</u>
<u>Converting this into standard form:</u>
- 3(x - 1)(x + 2) =
- 3(x² + x - 2) =
- 3x² + 3x - 6
The answer is B because you multiply 14 days (2 weeks) to 5 which is 70 then you add the other 22cm and that's how you would end up with 92cm
2x - 3 < 11 or 8x -10 < 82: <span>X < 23/2
<span>
Part 1</span>
</span>2x-3<11
Add 3 both sides
2x-3+3<11+3
Refine
2x<14
Divide by 2 on both sides
2x / 2 / 14 / 2
Refine
x < 7
<span>
Part 2</span>
8x-10<82
Add 10 to both sides
8x-10+10<82+10
Refine
8x<92
Divide by 8
8x / 8 / 92 / 8
Refine
x < 23 / 2
1.326 grams of NH3 are required to produce 4.65 g of HF.
Step-by-step explanation:
Balanced chemical reaction is written first to know the number of moles taking part in original reaction.
NH3 +3 F2 ⇒3 HF + NF3
Given:
mass of HF = 4.65
First the number of moles of HF in 4.65 grams is calculated by using the formula:
number of moles (n) = 
atomic mass of HF = 20 grams/mole
putting the values in the above equation number of moles can be found.
n = 
= 0.235 moles of HF are given.
From the equation it can be said that:
1 mole of NH3 reacts to form 3 moles of HF
so, x moles of NH3 would react to form 0.235 moles of HF
= 
3x = 0.235
x = 
x = 0.078 moles of NH3 is required.
The moles are converted to mass by applying the formula:
mass = atomic mass X number of moles (atomic mass of NH3 = 17 grams/mole)
putting the values in the formula
mass = 17 X 0.078
mass = 1.326 grams