Can sombody please help me with this math problem?
1 answer:
y=2/3y-3
1. y = 2/3 (9)-3 multiply 9 and 2 =18/3
y=18/3-3 divide 18 and 3 =6
y=6-3 subt. 3
y=3
2. -11=2/3x - 3
-11+3 = 2/3 x add 3 to both sides to cancel -3
-8=2/3 x
(3/2)-8 = (2/3)3/2 x multiply both sides by reciprical of 2/3
-24/2 = x divide
-12=x
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