Answer:
-10
Step-by-step explanation:
Velocity is the derivative of position. Derivative is defined as:
f'(x) = lim(h->0) [ f(x+h) - f(x) ] / h
s(t) = 1 - 10t
s(t+h) = 1 - 10(t+h)
Plugging in:
s'(t) = lim(h->0) [ 1 - 10(t+h) - (1 - 10t) ] / h
s'(t) = lim(h->0) (1 - 10t - 10h - 1 + 10t) / h
s'(t) = lim(h->0) (-10h) / h
s'(t) = lim(h->0) -10
s'(t) = -10
v(t) = -10
So at t=0, v(0) = -10.
Answer:
D
Step-by-step explanation:
Answer: Option a.
Step-by-step explanation:
To rationalize the expression you need to:
Multiply the numerator and the denominator by the conjugate of the denominator.
The conjugate of the denominator is: 
Remember that:
![(\sqrt[n]{x})^n=x\\\\(\sqrt[n]{x})(\sqrt[n]{y})=\sqrt[n]{xy}](https://tex.z-dn.net/?f=%28%5Csqrt%5Bn%5D%7Bx%7D%29%5En%3Dx%5C%5C%5C%5C%28%5Csqrt%5Bn%5D%7Bx%7D%29%28%5Csqrt%5Bn%5D%7By%7D%29%3D%5Csqrt%5Bn%5D%7Bxy%7D)
Therefore, multiplying the numerator and the denominator by the conjugate of the denominator (
), you get:

This is the option a.