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leonid [27]
3 years ago
5

Can someone help me with this​

Mathematics
1 answer:
SashulF [63]3 years ago
4 0

Answer:

\angle NRQ =85 \degree

Given:

\angle RPQ = 45 \degree \\  \angle PQR = (6x + 4)\degree \\  \angle NRQ = (15x - 5)\degree

Step-by-step explanation:

Property used: <em>An exterior angle of a triangle is equal to the sum of the opposite int</em><em>e</em><em>rior angles.</em>

<em>=  >  \angle RPQ +  \angle PQR =  \angle NRQ \\  \\  =  > 45 \degree + (6x + 4)\degree = (15x - 5)\degree \\  \\  =  > 45\degree + 6x\degree + 4\degree = 15x\degree - 5\degree \\  \\  =  > 49\degree  + 5 \degree= 15x\degree - 6x\degree \\  \\  =  > 54\degree = 9x\degree \\  \\  =  > 9x\degree = 54\degree \\  \\  =  > x\degree =  (\frac{54}{9} )\degree \\  \\  =  > x\degree = 6\degree \\  \\ Putting \: value \: of \: x \: in \:  \angle NRQ  \\   \\  =  > \angle NRQ = (15x - 5)\degree \\  \\  =  >  \angle NRQ = (15 \times 6 - 5) \degree \\  \\  =  >  \angle NRQ =85 \degree</em>

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The system of equations y=2x-1 and y=-1/4x+3 is shown on the graph below. What is a reasonable estimate for the solution?
statuscvo [17]

Answer:

Something close to (1.8,2.6)

Step-by-step explanation:

y=2x-1

y=-1/4 x+3

Since y=2x-1 and y=-1/4 x +3 then 2x-1=-1/4 x +3.

I'm going to multiply both sides by 4 to get rid of the fraction:

8x-4=-x+12

Add x on both sides:

9x-4=12

Add 4 on both sides:

9x=16

Divide both sides by 9:

x=16/9 is approximately 1.8 when put into calculator.

Now if x=16/9 and y=2x-1, then y=2(16/9)-1=32/9-1=32/9-9/9=(32-9)/9=23/9.

y=23/9 is approximately 2.6 when put into calculator.

So we are looking for an ordered pair pretty close to (1.8,2.6).

The graph is shown to you so I will put one here as well:

4 0
3 years ago
Is this correct?????
pickupchik [31]

Yes it’s correct my sister had something similar to that :)

7 0
3 years ago
Read 2 more answers
X + 3= 8x -11
lapo4ka [179]

The answer is x=2

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2+3=5

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6 0
3 years ago
Suppose that f(x) is an EVEN function and let the integral f(x) dx from 0 to 1=5 and the integral f(x) dx from 0 to 7 =1. What i
Cerrena [4.2K]
<span>Since it's even, the integral from -7 to -1 is the same as the integral from 1 to 7.
</span><span>think about
x^2 from 0..1,its 1/3
from 0..7 its 7^3/3
from -1..7 its 7^3/3+1/3
</span>
<span>from -7..-1 of x^2 its -1/3+7^3/3 to get this without integrating we just do 7^3/3-1/3 which is the integral from 0..7 minus the integral from 0..1
</span><span>So the integral from 1 to 0 f(x) dx = 5 changes to the integral from 0 to 1 f(x) dx = -5 and you add it to the integral from 0 to 7 which is 1 making -4</span>
4 0
3 years ago
State the y-coordinate of the y-intercept for the function below.
marta [7]

Answer:

1

Step-by-step explanation:

y-intercept is defined as the point where the graph crosses the y-axis. The value of x coordinate at this point is zero, as along entire y-axis, the value of x coordinate is always zero. So substituting x = 0 in the function will give us the y-coordinate of the y-intercept of the given function.

f(x)=x^{3}-x^{2} -x+1

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Thus, the y-coordinate of the y-intercept is 1. Therefore the y-intercept of the function in ordered pair will be: (0, 1)

3 0
3 years ago
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