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lesya [120]
3 years ago
9

Nico is saving money for his college education. He invests some money at 9​%, and ​$1700 less than that amount at 8% The investm

ents produced a total of ​$306 interest in 1 yr. How much did he invest at each​ rate?
Mathematics
1 answer:
Mashutka [201]3 years ago
5 0

Answer:

$2600 at 9%  and $900 at 8%

Step-by-step explanation:

Convert world problem to algebra:

(x*1.09)+((x-1700)*1.08) = (2x-1700)+306

Solve problem:

1.08 (x - 1700) + 1.09 x = 2 x - 1394

x=2600

first value is x (2600) and second value is 1700 less than x so its x-1700 (2600-1700=900)

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Perpendicular bisector of segment with endpoints -2,0 and 6,12.
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perpendicular slope= -2/3

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3 years ago
In the typing World 120 words in 3 minutes is average how many words could they type in 2 hours
Molodets [167]

Answer:

7,200 words

Step-by-step explanation:

7 0
3 years ago
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Brainliest for correct answer<br><br> A. 2<br><br> B. -2<br><br> C. 1/2<br><br> D. -1/2
seropon [69]

Answer:

B) -2

Step-by-step explanation:

I got the slope by using two points on the line (0,7) and (4,-1)

Slope=y2-y1/x2-x1

(7--1)/(0-4)

=

8/-4

I then simplified 8/-4 to -2

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3 years ago
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Can anyone please help!!!
quester [9]

Answer:

Question 9

(a) The distance, Jalaj walks in one day is 4.4 km

(b) The amount Jalaj raises after walking for 22 km at the end of the 5 days is $8

Question 10

(b) The difference between the largest and smallest areas is 2,400 m²

Step-by-step explanation:

Question 9

(a) The distance Jalaj walks in 5 days = 22 km

Whereby Jalaj walks equal distance every day, we have;

The distance, Jalaj walks in one day = 22 km/5 days = 4.4 km/day

The distance, Jalaj walks in one day = 4.4 km

(b) The amount he raises for every kilometer he walks = $1.60

The amount he raises after walking for 22 km at the end of the 5 days = 5 × $1.60  = $8

Question 10

(b) The given side length of the square = 120 meters to the nearest 10 meters

Therefore;

The maximum dimension for the side length of the square = 120 + 10/2 = 125

The largest possible area of the square, A_l = 125 m × 125 m = 15,625 m²

The minimum dimension for the side length of the square = 120 m - 10 m/2 = 115 m

The smallest possible area of the square, A_s = 115 m × 115 m = 13,225 m².

The difference between the largest and smallest areas, A_l - A_s = 15,625 - 13,225 = 2,400 m².

8 0
2 years ago
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