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liq [111]
2 years ago
11

A rancher’s herd of 250 sheep grazes over a 40-acre pasture. He would like to find out how many sheep are grazing on each acre o

f the pasture at any given time, so he has some images of the pasture taken by the state department of agriculture’s aerial photography division. Here are three samples of the images.
How do the sample statistics compare to the population mean and standard deviation?

Mathematics
1 answer:
ipn [44]2 years ago
5 0

Answer:

6.25

Step-by-step explanation:

250/40=6.25

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zmey [24]

Answer:

56

Step-by-step explanation:

@[email protected]

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3 years ago
-3.5 x 0.2 =??? ;w;<br><br><br> A. -0.7<br> B. 0.7<br> C. -3.3<br> D. -0.7
Dafna11 [192]

Answer:

A and D

Step-by-step explanation:

It can't be B because of the negative...

It would have to be less than 3.3 since 0.2 is less than and the 3.3 is negative

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3 0
2 years ago
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Stella [2.4K]
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2 years ago
Since the expression (x-4)^2+(y+1)^2 evaluated at (3,6) is
stiks02 [169]

\bf (x-4)^2+(y+1)^2\qquad (3,6)~~ \begin{cases} x = 3\\ y = 6 \end{cases}\implies (3-4)^2+(6+1)^2 \\\\\\ (-1)^2+7^2\implies 1+49\implies 50

5 0
3 years ago
17. Simplify (3 × 22) ÷ 6 + [28 – (4)2] = ?
Effectus [21]

Answer:

31

Step-by-step explanation:

(3*22=66) / 6 + [28n - (4)2=20]

66 /6 = 11+ [20]

11+20= 31

7 0
3 years ago
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