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TiliK225 [7]
3 years ago
15

What is the equation of the following line written in general form?

Mathematics
2 answers:
DENIUS [597]3 years ago
8 0

Answer:

x-y+1=0

Step-by-step explanation:

To find the equation of the line , use the points from the graph of the line

(1,2) and (4,5)

First frame equation of the line y=mx+b

slope (m)=\frac{y_2-y_1}{x_2-x_1} =\frac{5-2}{4-1} =1

m=1, (1,2)

y=mx+b

2=1(1)+b

b=1

So equation of the line is

y=1x+1

General form is Ax+By+C=0

Subtract 1x from both sides

y=1x+1

-1x+y=1, subtract 1 from both sides

-1x+y-1=0

Divide whole equation by -1

x-y+1=0

strojnjashka [21]3 years ago
4 0
Eq. of line through (1,2) and (4,5) is
y-y1= \frac{y2-y1}{x2-x1} (x-x1),
y-2= \frac{5-2}{4-1} (x-1)y-2= \frac{3}{3} (x-1)
y-2=x-1
y-2-x+1=0
y-x-1=0
x-y+1=0
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