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Anettt [7]
3 years ago
11

Convert 10 °C to degrees Fahrenheit ​

Mathematics
2 answers:
tatiyna3 years ago
7 0

Answer: 50

Step-by-step explanation:

Alenkasestr [34]3 years ago
5 0

Answer:

50ºF

Step-by-step explanation:

(10°C × 9/5) + 32 = 50°F

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Write the expression in standard form: 5(3a) + 8(-5b) + (4 * c * 6) * = Multiplication symbol
scoray [572]

Answer:

use photomath and your welcome :)))

5 0
3 years ago
Write the equation of the line in slope-intercept form that has the following points: (4, 5) (-1, 2)
Dima020 [189]

Answer:

C. y = 3/5x + 13/5

Step-by-step explanation:

8 0
3 years ago
2. what value of b makes the following equation true
Svetradugi [14.3K]

Answer:

  2. 10

  3. D.  1 for all n

Step-by-step explanation:

2. The applicable rules of exponents are ...

  (a^b)(a^c) = a^(b+c)

  a^b = 1/a^-b

__

  \dfrac{4^8}{(4^2)^{-3}}\div 4^4=\dfrac{4^8}{4^{-6}\cdot4^4}=\dfrac{4^8}{4^{-2}}\\\\=4^8\cdot4^2=4^{10}

The value of n is 10.

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3. Using the above rules of exponents, the expression simplifies to ...

  6^(-n+n) = 6^0 = 1

The value is 1 for any n.

4 0
3 years ago
Witch of the following expression is equivalent to the logarithmic expression below. log(3)5/x^2
BabaBlast [244]
Assuing you mean
log_{3}(\frac{5}{x^2})
remember that log(\frac{a}{b})=log(a)-log(b)
also, log(x^m)=(m)log(x)

so
log_{3}(\frac{5}{x^2})=
log_{3}(5)-log_{3}(x^2)=
log_{3}(5)-2log{3}(x)

the answer is B
4 0
3 years ago
Read 2 more answers
A survey of 85 families showed that 36 owned at least one DVD player. Find the 99% confidence interval estimate of the true prop
Katyanochek1 [597]

Answer:   (0.367,\ 0.473)

Step-by-step explanation:

The confidence interval for population mean is given by :-

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

, where \hat{p} is the sample proportion, n is the sample size , z_{\alpha/2} is the critical z-value.

Given : Significance level : \alpha:1-0.99=0.01

Sample size : n= 85

Critical value : z_{\alpha/2}=2.576

Sample proportion: \hat{p}=\dfrac{36}{85}\approx0.42

Now, the  99% confidence level will be :

\hat{p}\pmz_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}\\\\=0.42\pm(2.576)\sqrt{\dfrac{0.42(1-0.42)}{85}}\\\\\approx0.42\pm0.053\\\\=(0.42-0.053,\ 0.42+0.053)=(0.367,\ 0.473)

Hence, the  99% confidence interval estimate of the true proportion of families who own at least one DVD player is  (0.367,\ 0.473)

3 0
3 years ago
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