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Leni [432]
3 years ago
5

What is the relationship between ∠HIK and ∠JIK?

Mathematics
1 answer:
blagie [28]3 years ago
4 0
Complementary angles --- they add up to 90 degrees
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Which of the following best describes the equation below?
DanielleElmas [232]

Answer:

B

Step-by-step explanation:

3x+33+6x=9x-33

9x+33=9x-33

33=-33

no solution

7 0
3 years ago
Give two of your own examples of square roots that are irrational numbers and two rational numbers .
Vikentia [17]

Irrational

\sqrt{2}

\sqrt{3}

Rational:

\sqrt{1}

\sqrt{4}


6 0
3 years ago
Read 2 more answers
Find the equation of a line with a slope 3 that includes the point (0,5)
Genrish500 [490]

Answer:

B

Step-by-step explanation:

We want to find the equation of a line with a slope of 3 that includes the point (0, 5).

We can use the slope-intercept form, given by:

y=mx+b

Where m is the slope and b is the y-intercept.

Notice that the given point (0, 5) is already the y-intercept. So, b = 5.

By substitution, we acquire:

y=3x+5

Hence, our answer is B.

3 0
3 years ago
Read 2 more answers
an arts academy requires there to be 6 teachers for every 132 students and 3 tutors for every 27 students . how many students do
Nina [5.8K]

Answer:

3

Step-by-step explanation:

The number of necessary tutors when you divide 27 into 72, is 2.6; therefore the necessary number of tutors is 3 because you can’t have .6 of a tutor. Hope this helps!

4 0
2 years ago
A student created this table to represent a linear relationship between x and y.X Y-2. 10.0-1. 7.50. 5.01. 2.52. 0The student sa
alex41 [277]

The relationship between x and y is represent as:

Since, the relationship is linear.

The standard form of equation of line is:

y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1)

Consider any two set x and y values from the given relationship.

Let (-2, 10) and (-1,7.5)

\text{Substitute x}_1=-2,y_1=10,x_2=-1,y_2=7.5\text{ in the standard equation of line.}

\begin{gathered} y-y_1=\frac{y_2-y_1}{x_2-x_1}(x-x_1) \\ y-10=\frac{7.5-10}{-1-(-2)}(x-(-2)) \\ y-10=\frac{-2.5}{1}(x+2) \\ y-10=-2.5(x+2) \\ y=-2.5(x+2)+10 \end{gathered}

The equation of the linear relationship between x and y is:

y = -2.5(x + 2) + 10

Now, to check that the point (9, -17.5) lies on the represented relationship between x and y

Substitute x = 9 and y = -17.5 in the equation y = -2.5(x + 2) + 10

y = -2.5(x + 2) + 10

-17.5 = -2.5(9 + 2) + 10

-17.5 = -2.5(11) + 10

-17.5 = -27.5 + 10

-17.5 = -17.5

Thus, LHS = RHS

Hence the point (9, -17.5) lie on the given linear relationship between x and y.

Answer: The point (9, -17.5) lie on the given linear relationship between x and y.

8 0
1 year ago
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