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Gala2k [10]
3 years ago
5

How do I solve this?

Mathematics
1 answer:
Tanya [424]3 years ago
6 0
I'd like to help you with this problem
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a particular plant root grows 3.5 inches per month. how many centimeters is the plant root growing per month? (1 inch = 2.54 cen
dimaraw [331]
Since 1 inch is equal to 2.54 cm and the root grows 3.5 inches each month, we will do multiplication.

2.54 * 3.5 = 8.89

The plant root grows 8.89 centimeters each month.
3 0
3 years ago
Read 2 more answers
Find the upper bound
Paha777 [63]
The upper bound is 56cm I think
7 0
3 years ago
How do u do this? PLz show work!!!!
marissa [1.9K]
N:7=x remainder 2
⇒ n= 7*x +2
 
4n= 4*(7x+2)=28x+8=28x+7+1=7*(4x+1)+1
⇒ the remainder is 1
4 0
3 years ago
Read 2 more answers
URGENT!! Solve the following for θ, in radians, where 0≤θ<2π.
lidiya [134]

Answer:   0.93 radians & 2.21 radians

<u>Step-by-step explanation:</u>

-4sin^2\theta-3sin\theta+5=0\\\\\text{Since this is not factorable, use the quadratic formula to find the roots:}\\\\sin\theta=\dfrac{-(-3)\pm \sqrt{(-3)^2-4(-4)(5)}}{2(-4)}\\\\\\.\quad=\dfrac{3\pm \sqrt{9+80}}{-8}\\\\\\.\quad=\dfrac{3\pm\sqrt{89}}{-8}\\\\\\.\quad=\dfrac{3\pm9.43}{-8}\\\\\\.\quad=\dfrac{12.43}{-8}\quad and\quad \dfrac{-6.43}{-8}\\\\\\.\quad=-1.55\quad and\quad 0.80\\\\\\\theta=sin^{-1}(-1.55)\quad and\quad \theta=sin^{-1}(0.80)

\theta=not\ valid\qquad and\quad \theta=0.927

\theta = 0.927\ radians\text{\ in the 1st quadrant and}\\\pi-0.927=2.21\ radians\text{\ in the 2nd quadrant}

6 0
4 years ago
Read 2 more answers
Write 2/5 + 1/3 answer as a fraction. Show your work.
Diano4ka-milaya [45]

Answer: 11/15

Step-by-step explanation:2

5

+

1

3

=

2 × 3

5 × 3

+

1 × 5

3 × 5

=

6

15

+

5

15

=

6 + 5

15

=

11

15

8 0
3 years ago
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