You can upgrade lighting at your factory to LED bulbs that coast 6.95 each and last an average of 5 years.

Mathematics

1 answer:

miskamm [114]3 years ago

3 0

Answer:

$200

Step-by-step explanation:

Here is the full question

You can upgrade lighting at your factory to LED bulbs that cost $6.95 each and last an average of 5 years. It costs $3 in labor to change a bulb. Over a 10-year period, about how much will it cost per year to install LED bulbs in 100 lamps and change the bulbs when they burn out?

in 10 years, the bulbs would be changed twice

Total cost incurred per bulb in 10 years = (6.95 + $3) x 2 = $19.90

Since there are 100 bulbs, total cost incurred would be - $19.90 x 100 = $1990

Cost per year = $1990 / (6.95 + $3) = $200

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A single card is drawn from a standard 52-card deck. Let D be the event that the card drawn is a black card, and let F be the

Svetllana [295]

Answer:

$\dfrac{25}{26}$

Step-by-step explanation:

Let

D be the event that the card drawn is a black card
F be the event that the card drawn is a 10 card
F' be the event that the card drawn is not a 10 card

The probability

$Pr(D\cup F')=Pr(D)+Pr(F')-Pr(D\cap F')\\$

Note that

$Pr(D)=\dfrac{26}{52}=\dfrac{1}{2}\\ \\Pr(F)=\dfrac{4}{52}=\dfrac{1}{13}\\ \\Pr(F')=1-\dfrac{1}{13}=\dfrac{12}{13}\\ \\Pr(D\cap F')=\dfrac{24}{52}=\dfrac{6}{13}$