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2 years ago

Work out, giving your answer as a mixed number: 2/3 x 3 3/5

Mathematics

2 answers:

alekssr [168]2 years ago

6 0

Answer:

12/5 OR 2 2/5

Explanation:

I forgot what mixed numbers are so here are two answers! ;v;

I think It´s the second one though!

REY [17]2 years ago

3 0

Very ratstoztizgizgizhixhixh chchbut clol hxhlol CJ hi oh

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28. The edges of a cube are all increased by

Zolol [24]

Answer:

Percentage increase in volume will be

33.1

Step-by-step explanation:

Let the each edge of cube be

100

units.

Then its volume is

100

1000000

cubic units.

If each edge increases by

it becomes

110

units

and volume becomes

110

1331000

cubic units

Therefore increase in volume is

1331000

−

1000000

331000

cubic units

and percentage increase in volume is

331000

1000000

100

331

33.1

7 0

3 years ago

XD Plzzzzzz do 2 slides (4 problems)

Leya [2.2K]

Answer:

Slide 1:

1. Solution = (-3,2)

y = 2x - 1

y = 3/2x + 6

2. No solution

y = -4/2x + 4

y = -4/2x - 5

Slide 2:

3. Solution = (1, -6) ONE SOLUTION

4. Solution = (-4, -1) ONE SOLUTION

p.s i attached the graphs for problems 3 and 4. The first picture is for problem 3 and the second picture is for problem 4

I really hope this helped :)

6 0

3 years ago

The Town of Hertfordshire clerk knows that 23% of dogs in the town have completed emotional support training. Hertfordshire plan

Nataly_w [17]

Answer:

95.64% probability that under 30% of the dogs are emotional support trained

Step-by-step explanation:

For each dog, there are only two possible outcomes. Either they have completed emotional support training, or they have not. So we use the binomial probability distribution to solve this problem.

However, we are working with samples that are considerably big. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .