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3 years ago

Write a rule for the sequence then find the next three terms 24,27,30,33 . . .

Mathematics

2 answers:

Amanda [17]3 years ago

8 0

The rule is add 3. The next three terms are 36, 39, 42

never [62]3 years ago

5 0

Each number is adding 3 to get the next one. We can test this by applying this rule to the sequence of numbers.
24+3=27✅
27+3=30✅
30+3=33✅
This method is correct, so all we have to do is apply it to the last number to get the next one.
33+3=36
Hope this helps!

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Suppose that there are five young women and six young men on an island. Each woman is willing to marry some of the men on the is

pochemuha

Answer:

Based on the current information, the last man remaining unmarried will be a choice between two

Jason marries Anna

Matt marries Elizabeth

Kevin marries Barbara

Larry marries Diane

Carol can marry either Nick or Oscar

Step-by-step explanation:

The basic method to sort which woman will be marrying which man is simple.

We have to extract the choice by comparing choices of each woman side by side and then selecting the least common one and hence sorting one by one.

First, let's name all the women and men

1. Anna

2. Barbara

3. Carol

4. Diane

5. Elizabeth

We will refer to them with the initial letter of their name . A for Anna, B for Barbara, C for Carol, D for Diane, E for Elizabeth.

The men :

1. Jason

2. Larry

3. Matt

4. Kevin

5. Oscar

6. Nick

And they will be referred as J for Jason, L for Larry, M for Matt, K for Kevin, O for Oscar and N for Nick.

Options for A : J , L ,M

Options for B : K, L

Options for C : J, N , O

Options for D : J, L , N , O

Options for E : J, M

As we can see , no one else wants Kevin other than Barbara so :

Kevin marries Barbara

Moving onwards:

Elizabeth can marry either Jason or Matt,

Meanwhile Anna can marry either Jason , Larry or Matt

Hence,

Matt marries Eilzabeth

as Anna has two more choices still which are Jason and Larry.

Further, seeing the options for Carol and Diane

Carol can marry either Jason, Nick or Oscar while Diane can marry Larry as well as Jason , Nick and Oscar

We can select Jason as the match for Anna as Larry is also a choice for Diane.

Hence, Jason marries Anna

Now we are left with Larry , Nick and Oscar.

Since Carol can only decide from Nick and Oscar but Diane can decide from Larry, Nick and Oscar. Larry is the ideal option for Diane

so, Larry marries Diane

Now in the end, Carol can either choose between Nick or Oscar.

If she chooses Nick to marry, Oscar is left single

If she chooses Oscar to marry, Nick is left single.

7 0

3 years ago

Matt Bonner has 8 dimes, 9 pennies, and 4 quarters in his pocket. If each coin is equally likely to be pulled out of his pocket

Lesechka [4]

Answer:

B. 0.602%

Step-by-step explanation:

Probability is essentially (# times specific event will occur) / (# times general event will occur). Here, we have a few specific events: draw a quarter, draw a second quarter, draw a penny, and draw another penny. The general event will just be the number of coins there are to choose from.

The probability that the first draw is a quarter will be 4 / (4 + 8 + 9) = 4/21.

Since we've drawn one now, there's only 21 - 1 = 20 total coins left. The probability of drawing a second quarter is: (4 - 1) / (21 - 1) = 3/20.

The probability of drawing a penny is: 9 / (20 - 1) = 9/19.

The probability of drawing a second penny is: (9 - 1) / (19 - 1) = 8/18.

Multiply these four probabilities together:

(4/21) * (3/20) * (9/19) * (8/18) = 864 / 143640 ≈ 0.602%

The answer is B.

8 0

3 years ago

Read 2 more answers

Maria is asked to write down a prime number between 10 and 20 she writes down 17 is she right explain your answer

Wittaler [7]

Answer:

YES

Step-by-step explanation:

PRIME NUMBER BETWEEN 10 & 20 ARE 11,13,17,19-four

5 0

3 years ago

Read 2 more answers

PLEASE HELP IMAGE ATTACHED!!! the area of this parallelogram is 120mm^2. Find the value of X

Marta_Voda [28]

The area of a parallelogram is the base times the height so:

A=bh, in this case:

A=hx

x=A/h, we are told that A=120mm^2 and h=10mm so

x=120mm^2/10mm

x=12mm

3 0

3 years ago

4. What value of x makes the inequality true? 3(2x - 1) - 11x S -3x + 5

NNADVOKAT [17]

Answer:

A. {x: x ≥ -4}

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Distributive Property

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality

Algebra I

Terms/Coefficients
{Builder Set Notation}

Step-by-step explanation:

Step 1: Define

Identify

3(2x - 1) - 11x ≤ -3x + 5

Step 2: Solve for x

[Distributive Property Distribute 3: 6x - 3 - 11x ≤ -3x + 5
[Subtraction] Combine like terms: -5x - 3 ≤ -3x + 5
[Addition Property of Equality] Add 5x on both sides: -3 ≤ 2x + 5
[Subtraction Property of Equality] Subtract 5 on both sides: -8 ≤ 2x
[Division Property of Equality] Divide 2 on both sides: -4 ≤ x
Rewrite: x ≥ -4

6 0

2 years ago