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3 years ago

5

An oblique prism is created using rhombuses with edge lengths of 25 units. The area of one rhombus is 600 square units. The perp

endicular distance between the bases is 24 units.
What is the volume of the prism?

1 answer:

Semmy [17]3 years ago

8 0

Answer:

14400

Step-by-step explanation:

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The temperature on a summer afternoon is 76°F. Define a variable and write an expression to find the temperature after it change

Afina-wow [57]

Letting "c" be the value of the temperature change, looking at the choices, the nearest answer would be C. " 76 + c; 76 + (–8) = 68; 68°F ".

76 is the base or current temperature, then c would be the change in temperature experience. Since a decrease of 8 degrees is to be experienced, it is denoted by the negative symbol on 8.

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3 years ago

Which equation is a point slope form equation for line AB ?

kap26 [50]

Answer:

$y-5=\frac{3}{4}(x-6)$

Step-by-step explanation:

we know that

The equation of a line in point slope form is equal to

$y-y1=m(x-x1)$

step 1

Find the slope m

we have the points

A(-2,-1),B(6,5)

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the values

$m=\frac{5+1}{6+2}$

$m=\frac{6}{8}$

simplify

$m=\frac{3}{4}$

step 2

Find the equation of the line

we have

$(x1,y1)=(6,5)$

$m=\frac{3}{4}$

substitute

$y-y1=m(x-x1)$

$y-5=\frac{3}{4}(x-6)$

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3 years ago

A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang

laiz [17]

<u>Answer-</u>

a. Probability that three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

<u>Solution-</u>

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

$\binom{19}{3} = \frac{19!}{3!16!} = 969$

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

$\binom{33}{6} = \frac{33!}{6!27!} =1107568$

So total number of selection = (969)×(1107568) = 1073233392

Drawing 9 candies out of 52 candies,

$\binom{52}{9} = \frac{52!}{9!43!} = 3679075400$

∴P(3 white candies) = $\frac{1073233392}{3679075400} =0.29$

Total number of ways of selecting 3 whites, 2 are tans, 1 is pink, 1 is yellow, and 2 are greens is,

$\binom{19}{3} \binom{10}{2} \binom{7}{1} \binom{5}{1} \binom{6}{2}$

$=(\frac{19!}{3!16!}) (\frac{10!}{2!8!}) (\frac{7!}{1!6}) (\frac{5!}{1!4!}) (\frac{6!}{2!4!})$

$=(969)(45)(7)(5)(15)=22892625$

Total number of selection = 3 whites + 2 are tans + 1 is pink + 1 is yellow + 2 greens = 9 candies out of 52 candies is,

$\binom{52}{9}=\frac{52!}{9!43!} =3679075400$

∴ P( 3 whites, 2 are tans, 1 is pink, 1 is yellow, 2 greens) =

$\frac{22892625}{3679075400} = 0.006$

6 0

3 years ago