Help me please asap!!!
2 answers:
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Answer:
Step-by-step explanation:
Here X no of flight that reach on time has two outcomes only and each trial is independent of the other.
Since sample size is large we approximate to normal with mean =np and variance =npq
i.e. X is N(152,19.10)
is used for converting to std normal variate
Continuity correction of 0.5 on either side of interval would be applied for x
a)
=0.00
b)=1.00
c) p is N(0.76, sqrtpq/n)=N(0.76,0.0095)
P(p diff>0.03) =
=0.00