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2 years ago

??????????????????????

Mathematics

1 answer:

kakasveta [241]2 years ago

5 0

The answer is: [B]: "Rectangle, A = w * h square units" .
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HELP PLEASE!! 13 Points Offered

Sholpan [36]

Answer:

C: 124

Step-by-step explanation:

If you look at the angle it has to be over 90 degrees so therefore your only option is C: 124.

4 0

2 years ago

A bag contains 6 red apples and 5 yellow apples. 3 apples are selected at random. Find the probability of selecting 1 red apple

tester [92]

Answer: The required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

Step-by-step explanation: We are given that a bag contains 6 red apples and 5 yellow apples out of which 3 apples are selected at random.

We are to find the probability of selecting 1 red apple and 2 yellow apples.

Let S denote the sample space for selecting 3 apples from the bag and let A denote the event of selecting 1 red apple and 2 yellow apples.

Then, we have

$n(S)=^{6+5}C_3=^{11}C_3=\dfrac{11!}{3!(11-3)!}=\dfrac{11\times10\times9\times8!}{3\times2\times1\times8!}=165,\\\\\\n(A)\\\\\\=^6C_1\times^5C_2\\\\\\=\dfrac{6!}{1!(6-1)!}\times\dfrac{5!}{2!(5-2)!}\\\\\\=\dfrac{6\times5!}{1\times5!}\times\dfrac{5\times4\times3!}{2\times1\times3!}\\\\\\=6\times5\times2\\\\=60.$

Therefore, the probability of event A is given by

$P(A)=\dfrac{n(A)}{n(S)}=\dfrac{60}{165}=\dfrac{4}{11}\times100\%=36.36\%.$

Thus, the required probability of selecting 1 red apple and 2 yellow apples is 36.36%.

4 0

2 years ago

Simplified form of 12x-1 = 2(6+5x) +7

horrorfan [7]

X=10

12x-1=12+10x+7
2x=20
X=10

4 0

2 years ago

PLEASE HELP!!!!!!!!!!!!!!!!!!!!!!!

marishachu [46]

Answer:

32m^2

Step-by-step explanation:

32m^2

8*4 = 32

Have a nice day! :-)

6 0

3 years ago

Find the values of x and y leave answers in simplest radical form. *The altitude is:

jok3333 [9.3K]

$x = \sqrt{ { \sqrt{18} }^{2} + {2}^{2} } = \sqrt{18 + 4} = \sqrt{22} \\ y = \sqrt{ { \sqrt{18} }^{2} + {9}^{2} } = \sqrt{18 + 81} = \sqrt{99} = 3\sqrt{11}$

5 0

3 years ago