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3 years ago

What's the plotting points for two thirds

Mathematics

1 answer:

AfilCa [17]3 years ago

3 0

You would plot it at a reasonable distance between 0 and 1.

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The product of (x+2) (x-3) is

Aloiza [94]

Answer:

Step-by-step explanation:

$(x + 2)(x - 3)$

Multiply each term in the first parentheses by each term in the second parentheses ( FOIL)

$x(x - 3) + 2(x - 3)$

Calculate the product

${x}^{2} - 3x + 2x - 6$

Collect like terms

${x}^{2} - x - 6$

Hope this helps..

Best regards!

5 0

3 years ago

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How is the product of 2 and -5 shown on a number line

otez555 [7]

Answer: on point -10

Step-by-step explanation:

Because 2*-5 is -10.

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3 years ago

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How to slove - Tan x°= 1.11 and what is the answer?

jarptica [38.1K]

$\bf tan(x^o)=1.11\impliedby \textit{taking }tan^{-1}\textit{ to both sides}
\\\\\\
tan^{-1}[tan(x^o)]=tan^{-1}(1.11)\implies \measuredangle x=tan^{-1}(1.11)$

plug that in your calculator, make sure the calculator is in Degree mode

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3 years ago

The measure of <ABC is 90 degrees and the measure of <DBC is 33 degrees

Pavel [41]

Answer:

Step-by-step explanation:

4 0

3 years ago

For what values of k the relation R:{(k2 , 5), (3k, 6)} is not a function?

Nastasia [14]

Answer:

$k=0$ and $k=3$ .

Step-by-step explanation:

To this relation be a function, the horizontal coordinates can't be equal. So, let's find the value of $k$ that makes those coordinates equal.

$k^{2}=3k\\ k^{2}-3k=0\\k(k-3)=0\\$

Using the null factor property, we have

$k=0\\k-3=0 \implies k=3$

Therefore, the given relation is not a function when $k=0$ and $k=3$ .

7 0

3 years ago