Answer:
0, 10
Step-by-step explanation:
The given function is:

According to the quotient rule:

Applying the quotient rule:

The values for which g'(y) are zero are the critical points:

The critical values are y = 0 and y = 10.
Answer:
Step-by-step explanation:
Question (1)
x² + 10x + 12
= x² + 2(5x) + 5² - 5² + 12
= [x² + 2(5x) + 5²] - 5² + 12
= (x + 5)² - 25 + 12 [Since, a² + 2ab + b² = (a + b)²]
= (x + 5)² - 13
Question (2)
y² - 6y - 15
= y² - 2(3y) - 15
= y² - 2(3y) + 3² - 3² - 15
= [y² - 2(3y) + 3²] - 3² - 15 [Since, a² - 2ab + b² = (a - b)²]
= (y - 3)² - 3²- 15
= (y - 3)² - 9 - 15
= (y - 3)² - 24
Assuming you mean

first use chain rule on first part
derivitive of (x+1)⁵=5(x+1)⁴ times the derivitive of (x+1) which is 1
the first part is 5(x+1)⁴
derivitive of -5x is -5
derivitive of -2 is 0
we gots
f'(x)=5(x+1)⁴-5
find zeroes
0=5(x+1)⁴-5
5=5(x+1)⁴
1=(x+1)⁴
+/-1=x+1
-1+/-1=x
-2=x or 0=x
f'(x)=5(x+1)⁴-5
zeroes at x=-2 and x=0
Answer:
Following are the solution to this question:
Step-by-step explanation:
In this question, the graph file is missing so, its solution can be defined as follows:
When the bag includes 20 marbles, each will be drawn 5% of the time on average.
The bar chart shows that nearly 50% of the workforce red marbles are drawn, and about 25% of the time blue and white marbles are drawn. so, the equation is:

white marbles are available in the bag.
Answer: 12.5
Step-by-step explanation:
you go on the web and google area of trapezium