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2 years ago

Evaluate this exponential expression.

Mathematics

1 answer:

Afina-wow [57]2 years ago

8 0

It's -32 since 10-42=-32

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Solve the equation -5 = c/7

sweet-ann [11.9K]

Multiply both sides by 7.

-5 * 7 = c/7 * 7

-5 * 7 = c

c = -35

Your final answer is c = -35.

3 0

3 years ago

Read 2 more answers

A builder makes drainpipes that drop 1cm over a horizontal distance of 30cm to prevent clogs. A certain drainpipe needs to cover

Ann [662]

Answer:

700.39cm

Step-by-step explanation:

For a horizontal distance of 30cm, the drop is 1cm, now we need to get the drop for horizontal distance of 700 cm to maintain the same slope

Using the concept of cross multiplication

30cm=1 cm drop

700 cm=x

30x=700

X=700/30=70/3=23 ⅓

Utilizing pythagoras theorem, the length of pipe will be

L=√(23⅓)²+700²

L=700.38878092417 cm

Rounded off, the length is approximately 700.39 cm

8 0

2 years ago

Which number is greater? Explain. √20 , 10

Savatey [412]

Answer:

10 is greater because the square root of 20 is 4.47

Step-by-step explanation:

5 0

3 years ago

Solve the quadratic by factoring.<br> x^2-5x-31=5

torisob [31]

Answer:

$x = - 4\: or \: x = 9$

Step-by-step explanation:

make one side equal to zero:

${x}^{2} - 5x - 36 = 0$

find two factors that multiply to -36 and add to -5 (-9 & 4)

${x }^{2} - 9x + 4x - 36 = 0$

factorise

$x(x - 9) + 4(x - 9) = 0$

$(x + 4)(x - 9) = 0$

solve for x

$x = - 4 \: or \: x = 9$

5 0

3 years ago

Find the maximum value or minimum value for the function f(x) = 0.15(x + 1)² - 3.

il63 [147K]

Answer:

The minimum value for $f(x) = 0.15(x + 1)^2 - 3$ is $-3$ .

Step-by-step explanation:

Given function is $f(x) = 0.15(x + 1)^2 - 3$

We need to find the maximum value or the minimum value for the function.

Now, differentiate $f(x) = 0.15(x + 1)^2 - 3$ w.r.t $x$ .

$f'(x) =\frac{d}{dx}(0.15(x + 1)^2 - 3)\\f'(x)=\frac{d}{dx}(0.15(x+1)^2-\frac{d}{dx}(3)\\$

$f'(x)=2\times 0.15(x+1)\frac{d}{dx}(x+1)-0\\f'(x)=0.3(x+1)(1)\\f'(x)=0.3(x+1)$

Now, we will equate $f'(x)=0$ to find critical point.

$0.3(x+1)=0\\x=-1$

Plug this critical point in to the function $f(x) = 0.15(x + 1)^2 - 3$ we get,

$f(-1) = 0.15(-1 + 1)^2 - 3\\f(-1)=-3$

Also, $f''(x)=0.3$ which is positive, We have minimum value.

So, the minimum value for $f(x) = 0.15(x + 1)^2 - 3$ is $-3$ .

7 0

3 years ago