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3 years ago

6 is 55% of what number? Round answer to nearest tenth (1 number after decimal)

Mathematics

1 answer:

Arada [10]3 years ago

8 0

Answer:

10.9

Step-by-step explanation:

Formula = Number x 100

Percent = 6 x 100

55 = 10.91

Following shows the steps on how to derive this formula

Step 1: If 55% of a number is 6, then what is 100% of that number? Setup the equation.

55% = Y

100%

Step 2: Solve for Y

Using cross multiplication of two fractions, we get

55Y = 6 x 100

55Y = 600

Y = 600

100 = 10.91

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Answer:

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Step-by-step explanation:

He consumes 1/8 cups of berries per day, 1/8=1 day

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Number of days=(Number of cups of berries he has)/(The number of berries he consumes in a day)

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3 years ago

7. Find all geometric sequences such that the sum of the first two terms is 24 and the sum of the first

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Answer:

Step-by-step explanation:

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3 years ago

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4 years ago

Read 2 more answers

When circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%. Let

sergiy2304 [10]

Answer:

(a) P(X=3) = 0.093

(b) P(X≤3) = 0.966

(c) P(X≥4) = 0.034

(d) P(1≤X≤3) = 0.688

(e) The probability that none of the 25 boards is defective is 0.277.

(f) The expected value and standard deviation of X is 1.25 and 1.089 respectively.

Step-by-step explanation:

We are given that when circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%.

Let X = the number of defective boards in a random sample of size, n = 25

So, X ∼ Bin(25,0.05)

The probability distribution for the binomial distribution is given by;

$P(X=r)= \binom{n}{r} \times p^{r}\times (1-p)^{n-r} ; x = 0,1,2,......$

where, n = number of trials (samples) taken = 25

r = number of success

p = probability of success which in our question is percentage

of defectivs, i.e. 5%

(a) P(X = 3) = $\binom{25}{3} \times 0.05^{3}\times (1-0.05)^{25-3}$

= $2300 \times 0.05^{3}\times 0.95^{22}$

= 0.093

(b) P(X $\leq$ 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

= $\binom{25}{0} \times 0.05^{0}\times (1-0.05)^{25-0}+\binom{25}{1} \times 0.05^{1}\times (1-0.05)^{25-1}+\binom{25}{2} \times 0.05^{2}\times (1-0.05)^{25-2}+\binom{25}{3} \times 0.05^{3}\times (1-0.05)^{25-3}$

= $1 \times 1 \times 0.95^{25}+25 \times 0.05^{1}\times 0.95^{24}+300 \times 0.05^{2}\times 0.95^{23}+2300 \times 0.05^{3}\times 0.95^{22}$

= 0.966

(c) P(X $\geq$ 4) = 1 - P(X < 4) = 1 - P(X $\leq$ 3)

= 1 - 0.966

= 0.034

(d) P(1 ≤ X ≤ 3) = P(X = 1) + P(X = 2) + P(X = 3)

= $\binom{25}{1} \times 0.05^{1}\times (1-0.05)^{25-1}+\binom{25}{2} \times 0.05^{2}\times (1-0.05)^{25-2}+\binom{25}{3} \times 0.05^{3}\times (1-0.05)^{25-3}$

= $25 \times 0.05^{1}\times 0.95^{24}+300 \times 0.05^{2}\times 0.95^{23}+2300 \times 0.05^{3}\times 0.95^{22}$

= 0.688

(e) The probability that none of the 25 boards is defective is given by = P(X = 0)

P(X = 0) = $\binom{25}{0} \times 0.05^{0}\times (1-0.05)^{25-0}$

= $1 \times 1\times 0.95^{25}$

= 0.277

(f) The expected value of X is given by;

E(X) = $n \times p$

= $25 \times 0.05$ = 1.25

The standard deviation of X is given by;

S.D.(X) = $\sqrt{n \times p \times (1-p)}$

= $\sqrt{25 \times 0.05 \times (1-0.05)}$

= 1.089

8 0

3 years ago

A shipping company claims that 95% of packages are delivered on time. A student wants to conduct a simulation

NISA [10]

The average number of packages the led to be selected in order to find a package that was not delivered on time is 2.2 option first is correct.

<h3>What is simple random sampling?</h3>

With simple random sampling, each component of the population has an equal chance of being selected for the sample.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have:

A shipping company claims that 95% of packages are delivered on time.

From the table:

00- 04 is the package not delivered on time.

05-99 - package delivered on time.

The first simulation's third number, 31, 64, 04, is where you can locate an item that wasn't delivered on time.

The second simulation's second number, 34, 02, is the location of a late-delivered delivery.

The third simulation is equal to 96,00 - the second number, which is the location of a late package.

The second number where to find a shipment not delivered on time in the fourth simulation is 31,04

Where to find a box that wasn't delivered on time in the fifth simulation: 98, 01, second number

The average number = (3 + 2 + 2 + 2 + 2)/5

= 11/5

= 2.2

Thus, the average number of packages the led to be selected in order to find a package that was not delivered on time is 2.2 option first is correct.

Learn more about the simple random sampling here:

brainly.com/question/13219833

#SPJ1

5 0

2 years ago