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swat32
2 years ago
12

Someone please help me

Mathematics
2 answers:
juin [17]2 years ago
8 0

Answer:

1/1 = 1

Step-by-step explanation:

Use rise/run.

The x value increases by 1 in the same amount of time that the y value increases by 1. This gives you the slope 1/1 (y increase/x increase).

1/1 can then be converted to 1.

goldenfox [79]2 years ago
5 0

Answer:

the slope is -2

Step-by-step explanation:

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Help!!! I have no idea how to do this
aalyn [17]

Answer:

tan53=x/14

Step-by-step explanation:

solve after that with inverse tan and simple algebra

4 0
3 years ago
At a candy store, 3 giant lollipops sell for $7.59 and 2 small packets of bubblegum cost $4.82. Which is a better buy?
galben [10]
2 small backs of bubble gum is your answer because it costs less!!
3 0
3 years ago
If CE bisects ZBCD and if m ZBCE = 3x - 6
horrorfan [7]

Answer:

m∠BCD = 90°

∠BCD is a right angle

Step-by-step explanation:

<em>If a ray bisects an angle, that means it divides the angle into two equal parts in measure</em>

∵ Ray CE bisects ∠BCD

→ Means divide it into two angles BCE and ECD which equal in measures

∴ m∠BCE = m∠ECD = \frac{1}{2} m∠BCD

∵ m∠BCE = 3x - 6

∵ m∠ECD = 2x + 11

→ Equate them to find x

∴ 3x - 6 = 2x + 11

→ Add 6 to both sides

∵ 3x - 6 + 6 = 2x + 11 + 6

∴ 3x = 2x + 17

→ Subtract 2x from both sides

∵ 3x - 2x = 2x - 2x + 17

∴ x = 17

∵ m∠BCE =  \frac{1}{2} m∠BCD

→ Substitute x in the measure of ∠BCE to find it, then use it to

   find m∠BCD

∵ m∠BCE = 3(17) - 6 = 51 - 6

∴  m∠BCE = 45°

∵ 45 = \frac{1}{2} m∠BCD

→ Multiply both sides by 2

∴ 90 = m∠BCD

∴ m∠BCD = 90°

→ The measure of the acute angle is less than 90°, the measure of

   the obtuse angle is greater than 90°, and the measure of the

   right angle is 90°

∴ ∠BCD is a right angle

6 0
3 years ago
A club has members from three grades.
mars1129 [50]

the ratio is 24:30

or the simplified version is 4:5

7 0
2 years ago
If y=3x+5 and z=x^2+2x-5, what is yz?
Hitman42 [59]
<h3>Answer:  3x^3 + 11x^2 - 5x - 25</h3>

Work Shown:

yz = y(x^2+2x-5)

yz = y(x^2) + y(2x) + y(-5)

yz = x^2( y ) + 2x( y ) - 5( y )

yz = x^2( 3x+5 ) + 2x( 3x+5 ) - 5( 3x+5 )

yz = x^2*3x + x^2*5 + 2x*3x + 2x*5 - 5*3x - 5*5

yz = 3x^3 + 5x^2 + 6x^2 + 10x - 15x - 25

yz = 3x^3 + 11x^2 - 5x - 25

6 0
1 year ago
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