Answer:
f(2)=5
f(5)=33
Step-by-step explanation:
The given formula, that recursively defines the sequence is
![f(1) = 3 \\ f(n + 1) = 2f(n) - 1](https://tex.z-dn.net/?f=f%281%29%20%3D%203%20%5C%5C%20f%28n%20%2B%201%29%20%3D%202f%28n%29%20-%201)
When n=1, we obtain;
![f(1+ 1) = 2f(1) - 1 \\ f(2) = 2 \times 3 - 1 \\ f(2) = 6 - 1 \\ f(2) = 5](https://tex.z-dn.net/?f=f%281%2B%201%29%20%3D%202f%281%29%20-%201%20%5C%5C%20f%282%29%20%3D%202%20%5Ctimes%203%20-%201%20%5C%5C%20f%282%29%20%3D%206%20-%201%20%5C%5C%20f%282%29%20%3D%205)
When n=2, we get:
![f(2+ 1) = 2f(2) - 1 \\ f(3) = 2 \times 5 - 1 \\ f(3) = 10 - 1 \\ f(3) = 9](https://tex.z-dn.net/?f=f%282%2B%201%29%20%3D%202f%282%29%20-%201%20%5C%5C%20f%283%29%20%3D%202%20%5Ctimes%205%20-%201%20%5C%5C%20f%283%29%20%3D%2010%20-%201%20%5C%5C%20f%283%29%20%3D%209)
When n=3,
![f(3 + 1) = 2f(3) - 1 \\ f(4) = 2f(3) - 1 \\ f(4) = 2 \times 9 - 1 \\ f(4) = 18 - 1 \\ f(4) = 17](https://tex.z-dn.net/?f=f%283%20%2B%201%29%20%3D%202f%283%29%20-%201%20%5C%5C%20f%284%29%20%3D%202f%283%29%20-%201%20%5C%5C%20f%284%29%20%3D%202%20%5Ctimes%209%20-%201%20%5C%5C%20f%284%29%20%3D%2018%20-%201%20%5C%5C%20f%284%29%20%3D%2017)
When n=4
![f(4 + 1) = 2 f(4) - 1 \\ f(5) = 2 \times 17 - 1 \\ f(5) = 34 - 1 \\ f(5) = 33](https://tex.z-dn.net/?f=f%284%20%2B%201%29%20%3D%202%20f%284%29%20-%201%20%5C%5C%20f%285%29%20%3D%202%20%5Ctimes%2017%20-%201%20%5C%5C%20f%285%29%20%3D%2034%20-%201%20%5C%5C%20f%285%29%20%3D%2033)
When n=5,
![f(6) = 65](https://tex.z-dn.net/?f=f%286%29%20%3D%2065)
Answer:
y ≤ 3x
y > - 2x - 1
(1st choice)
Step-by-step explanation:
Ok jet the inverse is jut the function backwards,like a reciprocal.
So it should be D. (83,47)
Hope I could help you
Answer:
15.62 feet
Step-by-step explanation:
If the flagpole is 10ft tall and the shadow is 12ft long, and you need to find the distance from the top of the flagpole to the far end of the shadow, to get your answer, you must use the pythagorean theorum.
![a^{2} + b^{2} = c^{2}](https://tex.z-dn.net/?f=a%5E%7B2%7D%20%2B%20b%5E%7B2%7D%20%3D%20c%5E%7B2%7D)
let height of flagpole = a
let length of shadow = b
let distance between the two = c
![10^{2} + 12^{2} = c^{2} \\100 + 144 = c^{2}\\244 = c^{2}\\\sqrt{244} = \sqrt{c^{2}} \\\sqrt{244} = c\\15.62 = c](https://tex.z-dn.net/?f=10%5E%7B2%7D%20%2B%2012%5E%7B2%7D%20%3D%20c%5E%7B2%7D%20%5C%5C100%20%2B%20144%20%3D%20c%5E%7B2%7D%5C%5C244%20%3D%20c%5E%7B2%7D%5C%5C%5Csqrt%7B244%7D%20%3D%20%5Csqrt%7Bc%5E%7B2%7D%7D%20%5C%5C%5Csqrt%7B244%7D%20%3D%20c%5C%5C15.62%20%3D%20c)
6√5+10
Mark brainliest please
Hope this helps