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ser-zykov [4K]
3 years ago
15

In what quadrant does the imagen lie (3,-2), (3,-4) (,7,-2),(7,-4)

Mathematics
2 answers:
KiRa [710]3 years ago
6 0

Answer:

Quadrant 4

Step-by-step explanation:

IRISSAK [1]3 years ago
5 0
It lies in quadrant 4 because the x-value is positive and the y-value is negative.
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Jamal works as an electrician’s apprentice. He rewired 4 electrical outlets in 1 1/2 hours. If he works at the same pace for 7.5
RSB [31]

This can be solve by first solving the proportionality constant

Number electic outlets rewired is directly proportional to time spent

4 = (1 ½)a

Let be the proportionality constant

A = 8/3

O = (8/3)(7.5)

o = 20 outlets will jamal rewired if he works for 7.5 hrs 

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3 years ago
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Complete the point slope equation of the lone through (-8,-1) and (-6,5)​
sweet-ann [11.9K]

Answer:

slope m = (5+1)/(-6+8) = 6/2 =3

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Find The Solution set and draw a number line of each quad inequality
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Step-by-step explanation:

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3 years ago
A rectangular box which is open at the top can be made from an12-by-18-inch piece of metal by cutting a square from each corner
algol [13]

Answer:

h=2.35in, l=13.3in and w=7.3in

Step-by-step explanation:

In order to solve this problem, we must start by drawing a diagram that will represent the prolem. (Look at attached picture)

From the diagram we can see that the length ad the width of the box are found by  using the following expressions:

L=18-2x

W= 12-2x

H=x

next, we can make use of the volume formula of a rectangular prism, which is the following:

V=WLH

so we can substitute the expressions we got before on the formula:

V=x(12-2x)(18-2x)

and for ease of calculation, we can multiply the terms, so we get:

V=x(216-24x-36x+4x^{2})

V=x(4x^{2}-60x+216)

V=4x^{3}-60x^{2}+216x

So now we can find the derivative of the volume:

V'=12x^{2}-120x+216

and set it equal to zero, so we get:

12x^{2}-120x+216=0

and now we can solve. We can start by factoring the left side of the equation, so we get:

12(x^{2}-10x+18)=0

which yields:

x^{2}-10x+18=0

This one can only be solved by using the quadratic formula:

x=\frac{-b\pm \sqrt{-b^{2}-4ac}}{2a}

so we substitute the corresponding values:

x=\frac{-(-10)\pm \sqrt{-(-10)^{2}-4(1)(18)}}{2(1)}

which yields:

x=7.65in or x=2.35in

we keep the 2.35in only, because the 7.65in returns an impossible box, since that would make the width a negative width.

So the 2.35in height would give us the greatest box. Now we can use it to find the height, the width and the length of the box.

Height=x=2.35

W=12-2x=12-2*2.35=7.3in

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