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Nataliya [291]
3 years ago
11

A spring stretches 5.52 cm vertically when a 2.50 kg object is suspended from it. Find the distance (in cm) the spring stretches

if you replace the 2.50 kg object with a 3.40 kg object. Assume that the spring obeys the Hook's law.
Physics
1 answer:
svlad2 [7]3 years ago
7 0

Answer:

7.51 cm

Explanation:

y1 = 5.52 cm

m1 = 2.5 kg

m2 = 3.4 kg

Let the spring stretches by the distance y2.

According to Hooke's law

F = - k y

So, \frac{F_{1}}{F_{2}}=\frac{y_{1}}{y_{2}}

\frac{2.5 \times 9.8}{3.4 \times 9.8}}=\frac{5.52}{y_{2}}

y2 = 7.51 cm

Thus, the spring is stretches by 7.51 cm.

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An electromagnet is a device in which moving electric charges (current) in a coil of wire create a magnet. What’s one advantage
docker41 [41]
Electromagnets have certain advantages over permanent magnets. One of the major advantage is, the amount of electric current can easily be controlled, in turn, magnetic field can be controlled. Out of all the options, option D would be the best answer.

In short, Your Answer would be option D) Electromagnets can easily be turned on and off.

Hope this helps!
5 0
3 years ago
Which one does not affect the gravitational force between the 1 point
Zinaida [17]

Answer:

D. The net electrical charge of the Earth.

Explanation:

All the other three choices affect the gravitational force. I remember from middle school.

6 0
3 years ago
The motion of a particle along a straight line is described by the equation x=6+4t2 -t 4 , where x is in meter and t is in secon
Aleks [24]

Answer:

The position of the particle is 6m

The velocity of the particle is 16 m/s in negative direction

The acceleration of the object is -40 m/s²

Explanation:

Given;

motion of the particle along a straight line as x = 6 + 4t² - t⁴

The position of the object when t = 2s

x = 6 + 4(2)² - (2)⁴

x = 6 + 16 - 16

x = 6m

The velocity of the object when t = 2s

Velocity = dx/dt

dx/dt = 8t - 4t³

when t = 2s

Velocity = 8(2) - 4(2)³

Velocity = 16 - 32

Velocity = -16m/s

Velocity = 16 m/s (in negative direction)

The acceleration of the object when t = 2s

Acceleration = d²x/dt² = 8 - 12t²

Acceleration = 8 - 12 (2)²

Acceleration =  -40 m/s²

5 0
4 years ago
An object is attached to a vertical spring and slowly lowered to its equilibrium position. This stretches the spring by an amoun
trasher [3.6K]

Answer:

2d

Explanation:

For any instance equivalent force acting on the body is

mg-kd= m\frac{d}{dt}\frac{dx}{dt}

Where

m is the mass of the object

k is the force constant of the spring

d is the extension in the spring

and

d/dt(dx/dt)=  is the acceleration of the object

solving the above equation we get

x= Asin\omega t +d

where

\omega= \sqrt{\frac{k}{m} } = \frac{2\pi}{T}

A is the amplitude of oscillation from the mean position.

k= spring constant , T= time period

Here  we are assuming  that at t=T/4

x= 0   since, no extension in the spring

then

A=- d

Hence

x=- d sin wt + d

now, x is maximum when sin wt=- 1

Therefore,

x(maximum)=2d

7 0
3 years ago
Pls helppp :)List several examples of applied force, normal force, and friction that you’ve observed in your life.
Anon25 [30]

Answer:

an example for applied force is

Explanation:

The applied force is the force applied to the object to either displace it or change its shape.

5 0
3 years ago
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