1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Pani-rosa [81]
3 years ago
15

In the classic horse and cart problem, a horse is attached to a cart that can roll along on a set of wheels. Which of the follow

ing statement is true? Also explain the reason of your selected choice as well. a) The horse pulls on the cart with a force, and the cart pulls, back on the horse with an equal force. b) The horse pulls on the cart with a force greater than the force that the cart pulls back on the horse. c) The horse pulls the cart forward, because of a time delay between the action and reaction forces. d) The horse pulls the cart forward, but only if the horse has a mass greater than the mass of the cart. e) The horse pulls the cart forward because the force of friction forward is greater than the force of the wagon backward.
Physics
1 answer:
Marina86 [1]3 years ago
4 0
E is correct because net force in the forward direction is greater
You might be interested in
Two parallel plates have equal and opposite charges. When the space between the plates is evacuated, the electric field is E= 3.
svetlana [45]

Explanation:

The given data is as follows.

     Electric field between plates without dielectric, E_{1} = 3.50 \times 10^{5} V/m

   Electric field between the plates with dielectric, E_{2} = 2.40 \times 10^{5} V/m.

  Permittivity of free space, \epsilon_{o} = 8.85 \times 10^{-12} C^{2}/Nm^{2}

Now, we will determine the charge density as follows.

            \sigma_{i} = \epsilon_{o}(E_{1} - E_{2})

                 = 8.85 \times 10^{-12} \times (3.50 \times 10^{5} - 2.40 \times 10^{5})

                 = 9.735 \times 10^{-7} C/m^{2}

Thus, we can conclude that the charge density on each surface of the dielectric is 9.735 \times 10^{-7} C/m^{2}.

6 0
3 years ago
An elevator of massmis initially at rest onthe first floor of a building. It moves upward,and passes the second and third floors
Varvara68 [4.7K]

To solve this problem it is necessary to apply the concepts of Work. Work is understood as the force applied to travel a determined distance, in this case the height. The force in turn can be expressed by Newton's second law as the ratio between mass and gravity, as well

W = mgh

Where,

m = mass

h = height

g = Gravitational constant

When it ascends to the second floor it has traveled the energy necessary to climb a height, under this logic, until the 4 floor has traveled 3 times the height h of each of the floors therefore

h = 3h

Replacing in our equation we have to

W = mgh\\W = mg(3h)\\W = 3mgh

The correct answer is 4.

7 0
3 years ago
Write a 5-8 sentence summary on Earthquakes.
erastovalidia [21]

Answer:

An earthquake is a sudden shaking movement of the surface of the earth. It is known as a quake, tremblor or tremor. Earthquakes can range in size from those that are so weak that they cannot be felt to those violent enough to toss people around and destroy whole cities. ... An earthquake is measured on Richter's scale.

<h2><u>PLEASE MARK ME BRAINLIEST, PLEASE</u></h2>

3 0
3 years ago
Un movil viaja a 40km/h y comienza a reducir su velocidad a partir del instante t=0. Al cabo de 6 segundo se detiene completamen
aleksklad [387]

Answer:

1,85 m / s²

Explanation:

De la pregunta anterior, se obtuvieron los siguientes datos:

Velocidad inicial (u) = 40 km / h

Hora inicial (t₁) = 0

Tiempo final (t₂) = 6 s

Velocidad final (v) = 0

Aceleración (a) =?

A continuación, convertiremos 40 km / ha m / s. Esto se puede obtener de la siguiente manera:

1 km / h = 0,2778 m / s

Por lo tanto,

40 km / h = 40 km / h × 0,2778 m / s / 1 km / h

40 km / h = 11,11 m / s

Por tanto, 40 km / h equivalen a 11,11 m / s.

Finalmente, determinaremos la aceleración del móvil durante el período en el que desaceleró. Esto se puede obtener de la siguiente manera:

Velocidad inicial (u) = 11,11 m / s

Hora inicial (t₁) = 0

Tiempo final (t₂) = 6 s

Velocidad final (v) = 0

Aceleración (a) =?

a = (v - u) / (t₂ - t₁)

a = (0 - 11,11) / (6 - 0)

a = - 11,11 / 6

a = –1,85 m / s²

Por tanto, la aceleración del móvil durante el período en el que se ralentizó es de –1,85 m / s²

6 0
3 years ago
When is the pressure of the man on the ground more – lying position or standing
Wittaler [7]

Hi,

<u>The man on the ground in standing position has more pressure</u>. This is because when he stands, only his legs are in contact with the ground. While lying, his body is more in contact with the ground, therefore, he exerts less pressure.

To the point, a man standing position on the ground had more pressure.

More is the area of contact, less is the pressure efforted.

Thank you...

7 0
3 years ago
Other questions:
  • Shawn and his bike have a total mass of
    10·1 answer
  • How do you calculate acceleration?
    13·2 answers
  • A double slit produces a diffraction pattern that is a combination of single- and double-slit interference. Find the ratio of th
    11·2 answers
  • Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar. In a survey conduc
    14·1 answer
  • An equation for the frictional pressure loss Δ p (inches H2O) in a circular duct of inside diameter d (in.) and length L (ft) fo
    10·1 answer
  • What geological forces drive tectonic movements?
    11·2 answers
  • What influences the strength of an electric field?
    12·2 answers
  • A nuclear power plant operates at 79 percent of its maximum theoretical (Carnot) efficiency between temperatures of 700° and 330
    8·1 answer
  • 6) If nuclei A has a probability P of decaying in time t and nucleus B has a probability 2p of decaying in time t, which stateme
    13·1 answer
  • A 1500 kg aircraft going 35 m/s collides with a 2000 kg aircraft that is parked and they stick together after the collision and
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!